Question

好的，这是问题所在。

我有两个表，t1和t2。使用两个字段：

产品
POSTED_TRAN_AMT（在t1中）
BEG_AUM_AMT（在t2中）

我想找到一个期间（AP = 202，FY = 2017）的产品POSTED_TRAN_AMT和BEG_AUM_AMT不同。

目前我被困在这里：

select PRODUCT, sum(POSTED_TRAN_AMT) from t1 
where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 and ACCOUNT = '995050' 
group by product

union all 

select PRODUCT sum(_BEG_AUM_AMT) from t2 
 where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 group by product

注意：手动excel搜索后，优秀产品（值为0）出现在t2

中

Answer 1

将它们写为子查询并加入

with t1 as (
    select PRODUCT, 
           sum(POSTED_TRAN_AMT) as POSTED_TRAN_AMT
    from t1 
    where FISCAL_YEAR = 2017 
    and ACCOUNTING_PERIOD = 202 
    and ACCOUNT = '995050' 
    group by product
) , t2 as (
    select PRODUCT,
          sum(BEG_AUM_AMT) as BEG_AUM_AMT
    from t2 
    where FISCAL_YEAR = 2017 
    and ACCOUNTING_PERIOD = 202 
    group by product
) 
select t1.product, 
       t1.POSTED_TRAN_AMT,
       t2.BEG_AUM_AMT
from t1 
     join t2 on t1.product = t2.product
where  t1.POSTED_TRAN_AMT != t2.BEG_AUM_AMT

如果差异可能是t1但不是t2中的PRODUCT，则需要使用外连接并修改WHERE子句，如下所示：

select t1.product, 
       t1.POSTED_TRAN_AMT,
       t2.BEG_AUM_AMT
from t1 
     left outer join t2 on t1.product = t2.product
where  (  t2.product is null 
          or t1.POSTED_TRAN_AMT != t2.BEG_AUM_AMT
         )

如果您不知道PRODUCT可能在使用full outer join时丢失哪个表格，并检查两个表格中的空值：

select coalesce(t1.product, t2.product) as product, 
       t1.POSTED_TRAN_AMT,
       t2.BEG_AUM_AMT
from t1 
     full outer join t2 on t1.product = t2.product
where  (  t1.product is null 
          or t2.product is null 
          or t1.POSTED_TRAN_AMT != t2.BEG_AUM_AMT
         )

＆＃34;我也尝试了不同的查询，但即使创建了连接，它也会将值相乘。你知道为什么会出现这种乘法吗？＆＃34;

我的查询会比较汇总值，而您的版本则不会。一个变体是：

select A.product, 
sum(A.POSTED_TRAN_AMT),
 sum(B.BEG_AUM_AMT) 
 from A 
      join 
     B on A.product = B.product 
       and A.FISCAL_YEAR = B.FISCAL_YEAR 
       and A.ACCOUNTING_PERIOD = B.ACCOUNTING_PERIOD  
   where  A.FISCAL_YEAR = 2017 
   and A.ACCOUNTING_PERIOD = 202 
   and A.ACCOUNT = '995050' 
  group by A.product having  sum(A.POSTED_TRAN_AMT) != sum(B.BEG_AUM_AMT)

Answer 2

这可能是一个过于复杂和缓慢的方法，但它没有假设每个PRODUCT都在两个表中。

它对您已创建的两个摘要执行FULL OUTER JOIN以比较它们。 FULL OUTER JOIN将确保您的结果包含两个表中 中的每个产品。

WITH t1sum AS (SELECT product, SUM (posted_tran_amt) total_amount FROM t1 WHERE fiscal_year = 2017 AND accounting_period = 202 AND account = '995050' GROUP BY product), t2sum AS (SELECT product, SUM (beg_aum_amt) total_amount FROM t2 WHERE fiscal_year = 2017 AND accounting_period = 202 GROUP BY product) SELECT NVL (t1sum.product, t2sum.product) product, t1sum.total_amount, t2sum.total_amount FROM t1sum FULL OUTER JOIN t2sum ON t1sum.product = t2sum.product WHERE (t1sum.total_amount IS NULL AND t2sum.total_amount IS NOT NULL) OR (t1sum.total_amount IS NOT NULL AND t2sum.total_amount IS NULL) OR (t1sum.total_amount != t2sum.total_amount)

Answer 3

根据我对您的要求的理解，您的查询应该如下所示

(
select PRODUCT, sum(POSTED_TRAN_AMT) from t1 
where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 and ACCOUNT = '995050' 
group by product

minus

select PRODUCT, sum(_BEG_AUM_AMT) from t2 
 where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 group by product
)
union
(
select PRODUCT sum(_BEG_AUM_AMT) from t2 
 where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 group by product

minus

select PRODUCT, sum(POSTED_TRAN_AMT) from t1 
where FISCAL_YEAR = 2017 and ACCOUNTING_PERIOD = 202 and ACCOUNT = '995050' 
group by product

)

SQL - 在两个表中查找错误匹配值

3 个答案: