我正在尝试编写一个perl代码来解析多个JSON消息。我写的perl代码只解析了JSON文件只包含一条json消息时的值。但是当该文件中有多条消息时它会失败。它抛出错误:" Undefined subroutine& Carp :: shortmess_heavy"。 JSON文件采用以下格式:
{
"/test/test1/test2/test3/supertest4" : [],
"/test/test1/test2/test3/supertest2" : [
{
"tag1" : "",
"tag2" : true,
"tag3" : [
{
"status" : "TRUE",
"name" : "DEF",
"age" : "28",
"sex" : "f"
},
{
"status" : "FALSE",
"name" : "PQR",
"age" : "39",
"sex" : "f"
}
],
"tag4" : "FAILED",
"tag5" : "/test/test1/test2/test3/supertest2/test02",
"tag6" : ""
}
],
"/test/test1/test2/test3/supertest1" : [
{
"tag1" : "",
"tag2" : false,
"tag3" : [
{
"status" : "TRUE",
"name" : "ABC",
"age" : "21",
"sex" : "m"
},
{
"status" : "FALSE",
"name" : "XYZ",
"age" : "34",
"sex" : "f"
}
],
"tag4" : "PASSED",
"tag5" : "/test/test1/test2/test3/supertest1/test01",
"tag6" : ""
}
],
"/test/test1/test2/test3/supertest6" : []
}
我的perl代码用于解析单个JSON消息:
use strict;
use warnings;
use Data::Dumper;
use JSON;
use JSON qw( decode_json );
my $json_file = "tmp1.json";
my $json;
open (my $fh, '<', $json_file) or die "can not open file $json_file";
{ local $/; $json = <$fh>; }
close($fh);
my $decoded = decode_json($json);
print "TAG4 = " . $decoded->{'tag4'} . "\n";
print "TAg5 = " . $decoded->{'tag5'} . "\n";
my @tag3 = @{ $decoded->{'tag3'} };
foreach my $tg3 ( @tag3 ) {
print "Name = ". $tg3->{"name"} . "\n";
print "Status = ". $tg3->{"status"} . "\n";
print "Age = ". $tg3->{"age"} . "\n";
}
请帮忙。
谢谢!
答案 0 :(得分:3)
要解析多个JSON对象,请使用JSON :: XS的增量解析。
my $json = '{"foo":"bar"} ["baz"] true';
my @results = JSON::XS->new->incr_parse($json);
use Data::Dumper;
print Dumper \@results;
输出:
$VAR1 = [
{
'foo' => 'bar'
},
[
'baz'
],
bless( do{\(my $o = 1)}, 'JSON::PP::Boolean' )
];