如何创建用作选择器的视图控制器?它在当前上下文中从屏幕底部显示,并且仅覆盖屏幕的一部分。选择一个值后,会将其传递回在iOS中显示选择器的视图控制器。
答案 0 :(得分:0)
在目标C中尝试:
UIAlertController *alert = [UIAlertController alertControllerWithTitle:@"Success" message:@"Thank you for coming here" preferredStyle:UIAlertControllerStyleAlert];
UIAlertAction *okAction = [UIAlertAction actionWithTitle:@"Ok" style:UIAlertActionStyleDefault handler:^(UIAlertAction * action){
//define your custom action here or data passing here
[self dismissViewControllerAnimated:YES completion:nil];
}];
[alert addAction:okAction];
[self presentViewController:alert animated:YES completion:nil];
答案 1 :(得分:0)
尝试使用以下有用的库:
https://github.com/madjid/MMPickerView
代码段
NSArray *strings = @[@"This", @"is", @"just", @"an array", @"of strings."];
[MMPickerView showPickerViewInView:self.view
withStrings:strings
withOptions:nil
completion:^(NSString *selectedString) {
//selectedString is the return value which you can use as you wish
self.label.text = selectedString;
}];
答案 2 :(得分:0)
添加UIViewController和您想要的设计..为该视图控制器提供一个Stroyboard ID ... 在选择器视图控制器类
中添加以下代码check.php
当用户didSelectRowAtIndexPath ..
时var mainVC : YourSendingClassName!
现在在你的发送者课程中,如果你想使用一个按钮从中创建一个动作...根据你的要求,按钮应该在底部..
在Button Action
中添加以下代码 call self.dismiss(true , completion {
self.mainVC.userPickedValue(theValueYouWannaPass)
})
动作后创建一个函数
let sliderViewController = storyboard?.instantiateViewController(withIdentifier: "YourStoryBoard ID") as! YourPickerClass
sliderViewController.modalPresentationStyle = .popover
//set width and height as you need
sliderViewController.preferredContentSize = CGSize(width: 253, height: 160)
sliderViewController.mainVC = self
let popoverMenuViewController = sliderViewController.popoverPresentationController
popoverMenuViewController?.permittedArrowDirections = .down
popoverMenuViewController?.delegate = self
popoverMenuViewController?.sourceView = sender
popoverMenuViewController?.sourceRect = sender.frame
present(sliderViewController, animated: true, completion: nil)