Question

所以要获取摄像机列表并让用户选择一个（C ++，Boost，dshow，windows），我使用这样的代码：

#include "StdAfx.h"
#include "list.h"
#include <windows.h>
#include <dshow.h>
#include <boost/lexical_cast.hpp>

HRESULT CamerasList::EnumerateDevices( REFGUID category, IEnumMoniker **ppEnum )
{
    // Create the System Device Enumerator.
    ICreateDevEnum *pDevEnum;
    HRESULT hr = CoCreateInstance(CLSID_SystemDeviceEnum, NULL,  
        CLSCTX_INPROC_SERVER, IID_PPV_ARGS(&pDevEnum));

    if (SUCCEEDED(hr))
    {
        // Create an enumerator for the category.
        hr = pDevEnum->CreateClassEnumerator(category, ppEnum, 0);
        if (hr == S_FALSE)
        {
            hr = VFW_E_NOT_FOUND;  // The category is empty. Treat as an error.
        }
        pDevEnum->Release();
    }
    return hr;
}

int CamerasList::SelectFromList()
{   int i = 0;
    int SelectedIndex;
    IEnumMoniker *pEnum;
    printf("\nLet us select video device\n");
    printf("Available Capture Devices are:\n");
    HRESULT hr;
    hr = EnumerateDevices(CLSID_VideoInputDeviceCategory, &pEnum);
    if (SUCCEEDED(hr))
    {
        IMoniker *pMoniker = NULL;

        while (pEnum->Next(1, &pMoniker, NULL) == S_OK)
        {
            IPropertyBag *pPropBag;
            HRESULT hr = pMoniker->BindToStorage(0, 0, IID_PPV_ARGS(&pPropBag));
            if (FAILED(hr))
            {
                pMoniker->Release();
                continue;  
            } 

            VARIANT var;
            VariantInit(&var);

            // Get description or friendly name.
            hr = pPropBag->Read(L"Description", &var, 0);
            if (FAILED(hr))
            {
                hr = pPropBag->Read(L"FriendlyName", &var, 0);
            }
            if (SUCCEEDED(hr))
            {
                std::cout << i;
                printf(") %S\n", var.bstrVal);
                i++;
                VariantClear(&var); 
            }

            hr = pPropBag->Write(L"FriendlyName", &var);

            pPropBag->Release();
            pMoniker->Release();

        }
        SelectedIndex = 999;
    if (i <= 0)
    {
        cout <<"No devices found. \n " << endl;
        //cout <<"Please restart application."  << endl;
        //cin.get();
        //Sleep(999999);
    return 999;

    }else if(i == 1){
            cout <<"Default device will be used\n" << std::endl;
            SelectedIndex = 0;
        }else{
        while(SelectedIndex > i-1 || SelectedIndex < 0)
        {
            try{        
            std::string s;
            std::getline( cin, s, '\n' );
            SelectedIndex =  boost::lexical_cast<int>(s);
            }
            catch(std::exception& e){
                std::cout <<"please input index from 0 to " << i-1 << std::endl;
                SelectedIndex = 999;
            }
        }}
        pEnum->Release();
    }else
    {
        printf("no Video Devices found. \n") ;
        //cout <<"Please restart application."  << endl;
        //cin.get();
        //Sleep(999999);
        return 999;
    }
    return SelectedIndex;
}

我需要以某种方式获取所选相机的相机支持分辨率列表。怎么做这个？

Answer 1

假设您已将捕获源过滤器添加到图表中：一种方法是获取捕获过滤器输出引脚的IAMStreamConfig接口，然后调用IAMStreamConfig :: GetNumberOfCapabilities以获取设备支持的格式功能的数量。您可以通过使用适当的索引调用IAMStreamConfig :: GetStreamCaps来迭代所有格式。

Answer 2

您可以在不将捕获源添加到过滤器图形的情况下获得支持的分辨率。你需要

将设备moniker绑定到基座filter
从该过滤器获取输出pin
枚举该输出引脚的media types

以下是如何在给定media type enumerator

的情况下枚举媒体类型

AM_MEDIA_TYPE* mediaType = NULL;
VIDEOINFOHEADER* videoInfoHeader = NULL;
while (S_OK == mediaTypesEnumerator->Next(1, &mediaType, NULL))
{
    if ((mediaType->formattype == FORMAT_VideoInfo) &&
        (mediaType->cbFormat >= sizeof(VIDEOINFOHEADER)) &&
        (mediaType->pbFormat != NULL))
    {
        videoInfoHeader = (VIDEOINFOHEADER*)mediaType->pbFormat;
        videoInfoHeader->bmiHeader.biWidth;  // Supported width
        videoInfoHeader->bmiHeader.biHeight; // Supported height
    }
    FreeMediaType(*mediaType);
}

Windows：如何获得支持摄像头的分辨率？

2 个答案: