为什么firstHalf.indexOf(secondHalfArr[i])
0
?
"use strict";
let word = "9999999999",
len = word.length,
oddSecondHalfStarter = (len % 2 == 0) ? len / 2 : 1 + len / 2,
firstHalf = word.substr(0, len / 2),
secondHalf = word.substr(oddSecondHalfStarter, len),
firstHalfArr = word.substr(0, len / 2).split(''),
secondHalfArr = word.substr(oddSecondHalfStarter, len).split(''),
firstHalfLength = firstHalf.length,
secondHalfLength = secondHalf.length,
charsToReplace = 0;
for (let i = 0; i < firstHalfLength; i++) {
if (firstHalf.indexOf(secondHalfArr[i]) < 1) {
charsToReplace++;
}
}
for (let i = 0; i < secondHalfLength; i++) {
if (secondHalf.indexOf(firstHalfArr[i]) < 1) {
charsToReplace++;
}
}
alert(charsToReplace);
答案 0 :(得分:1)
indexOf()
方法返回字符串中第一次出现指定值的位置。
如果要搜索的值永远不会发生,则此方法返回 -1 。 indexOf()
方法区分大小写。
请务必在语句中使用!== -1
以获得有效结果。
示例:强>
for (let i = 0; i < secondHalfLength; i++) {
if (secondHalf.indexOf(firstHalfArr[i]) !== -1) {
charsToReplace++;
}
}