Question

我有一个SKShapeNode，如果满足特定条件，它需要将每个角的四舍五入。阅读下面的链接提供的答案，这似乎很容易安静，因为我只是使用| =来舍入需要舍入的额外角（4x if语句）。

How to write a generic UIRectCorner function?

然而，这不起作用！当我使用下面的代码时，我收到错误消息＆＃34; Binart operator＆＃39; | =＆＃39;不能适用于两个UIRectCorner＆＃39;操作数＆＃34;

var corners: UIRectCorner = UIRectCorner(rawValue: 0) | UIRectCorner(rawValue: 1)

或

var corners: UIRectCorner = UIRectCorner(rawValue: 0)
corners |= UIRectCorner(rawValue: 1)

我一定是做错了什么，但我无法弄明白什么？任何帮助将非常感激。

Answer 1

我写了一个非常方便的扩展，我在所有SpriteKit游戏中大量使用。它需要现有的SKShapeNode并复制其所有相关属性，然后删除并创建一个新的，指定要舍入的任何角。注意：如果形状节点有任何子节点，则不应使用此节点，因为它们不会在新创建中保留。因此，在向其中添加任何子项之前，请始终使用此方法。

shapeNode.roundCorners(topLeft:true,topRight: true,bottomLeft:false,bottomRight:false,radius:20,parent:self)


extension SKShapeNode {
    func roundCorners(topLeft:Bool,topRight:Bool,bottomLeft:Bool,bottomRight:Bool,radius: CGFloat,parent: SKNode){
        let newNode = SKShapeNode(rect: self.frame)
        newNode.fillColor = self.fillColor
        newNode.lineWidth = self.lineWidth
        newNode.position = self.position
        newNode.name = self.name
        newNode.fillColor = self.fillColor
        newNode.strokeColor = self.strokeColor
        newNode.fillTexture = self.fillTexture
        self.removeFromParent()
        parent.addChild(newNode)
        var corners = UIRectCorner()
        if topLeft { corners = corners.union(.bottomLeft) }
        if topRight { corners = corners.union(.bottomRight) }
        if bottomLeft { corners = corners.union(.topLeft) }
        if bottomRight { corners = corners.union(.topRight) }
        newNode.path = UIBezierPath(roundedRect: CGRect(x: -(newNode.frame.width / 2),y:-(newNode.frame.height / 2),width: newNode.frame.width, height: newNode.frame.height),byRoundingCorners: corners, cornerRadii: CGSize(width:radius,height:radius)).cgPath
    }
}

Answer 2

排序解决了我的问题。 | =和+ =没有工作，但= [previousValue，newValue]似乎有效。我的代码如下。如果有更好的方法，请告诉我。

func roundCorners() {

    let TR = true
    let TL = true
    let BR = false
    let BL = true

    var corners: UIRectCorner = []

    if TR == true {
        corners = [corners, .topRight]
    }

    if TL == true {
        corners = [corners, .topLeft]
    }

    if BR == true {
        corners = [corners, .bottomRight]
    }

    if BL == true {
        corners = [corners, .bottomLeft]
    }

    let rect = CGRect(x: -50, y: -50, width: 100, height: 100)
    let cornerSize = CGSize(width: 10, height: 10)

    let shape = SKShapeNode()
    shape.fillColor = UIColor.black
    shape.path = UIBezierPath(roundedRect: rect, byRoundingCorners: corners, cornerRadii: cornerSize).cgPath
    addChild(shape)

}

Answer 3

Swift 5.2.x：

extension SKShapeNode {
    convenience init(corners:UIRectCorner, size:CGSize, radius:CGFloat) {
        // flips corners vertically for UIBezierPath and SKSpriteKit
        var flipCorners = UIRectCorner()
        flipCorners = corners.contains(.topLeft) ? flipCorners.union(.bottomLeft): flipCorners
        flipCorners = corners.contains(.topRight) ? flipCorners.union(.bottomRight): flipCorners
        flipCorners = corners.contains(.bottomLeft) ? flipCorners.union(.topLeft): flipCorners
        flipCorners = corners.contains(.bottomRight) ? flipCorners.union(.topRight): flipCorners
        self.init(path: UIBezierPath.init(roundedRect: CGRect(origin:CGPoint.zero,size:size), byRoundingCorners: flipCorners, cornerRadii: CGSize(width: radius, height: radius)).cgPath)
    }
}

用法：

let roundedShape = SKShapeNode(corners: UIRectCorner([.topLeft,.topRight]), size: CGSize(width:200,height:100), radius: 16)

圆形特定角落 - SKShapeNode

3 个答案:

Swift 5.2.x：

用法：