Question

我在下面有一个SQL查询，我想使用FOR XML语法格式化为XML。

SELECT
  gr.id,
  gr.created,
  ts.ordernumber
FROM trGrouped gr
INNER JOIN transactions ts
  ON ts.grouped_id = gr.id
WHERE ts.ordernumber IN ('4003970100000383', '4003970100000376', '4003970100000369', '1022108100000018')

这是我希望查询看起来像XML格式的一个例子。

<trans_groups>
  <grouped id="56" created="4/14/2017">
    <ordernumber>1022108100000001</ordernumber>
    <ordernumber>1022108100000002</ordernumber>
    <ordernumber>1022108100000003</ordernumber>
  </grouped>
  <grouped id="57" created="4/14/2017">
    <ordernumber>1022109100000001</ordernumber>
    <ordernumber>1022109100000002</ordernumber>
  </grouped>
</trans_groups>

到目前为止，我还没有能够做到这一点。我尝试了以下但是这不是对订单进行分组。

select gr.id as [@id], gr.created as [@created],
    (
    SELECT ts.ordernumber as ordernumber
    )
FROM trGrouped gr inner join transactions ts on ts.grouped_id = gr.id
    where ts.ordernumber in('4003970100000383', '4003970100000376', '4003970100000369', '1022108100000018')
FOR XML PATH('grouped'), ROOT('trans_groups')

Answer 1

这是一种方法

示例

Declare @YourTable table (id int,created date, ordernumber varchar(25)) Insert Into @YourTable values (56,'04/14/2017','1022108100000001') ,(56,'04/14/2017','1022108100000002') ,(56,'04/14/2017','1022108100000003') ,(57,'04/14/2017','1022109100000001') ,(57,'04/14/2017','1022109100000002') Select [@id] = id ,[@created] = convert(VARCHAR(10), created, 101) ,( Select ordernumber From @YourTable A1 Where A1.id = A.id For XML Path(''), type ) From (Select Distinct ID,Created From @YourTable ) A For XML Path('grouped'), Root('trans_groups')

<强>返回

<trans_groups> <grouped id="56" created="04/14/2017"> <ordernumber>1022108100000001</ordernumber> <ordernumber>1022108100000002</ordernumber> <ordernumber>1022108100000003</ordernumber> </grouped> <grouped id="57" created="04/14/2017"> <ordernumber>1022109100000001</ordernumber> <ordernumber>1022109100000002</ordernumber> </grouped> </trans_groups>

Answer 2

这对我有用。

select gr.id as [@id], gr.created as [@created],
    (
    SELECT ordernumber as ordernumber from transactions where grouped_id = grouped_id
    and ordernumber in ('4003970100000383', '4003970100000376', '4003970100000369', '1022108100000018')
    FOR XML path(''), type
    )
FROM (SELECT distinct gr.id, created FROM trGrouped gr inner join transactions ts on ts.grouped_id = gr.id
    where ts.ordernumber in('4003970100000383', '4003970100000376', '4003970100000369', '1022108100000018')) gr 
FOR XML PATH('grouped'), ROOT('trans_groups')

使用FOR XML对2个sql表进行分组

2 个答案: