shell脚本

Question

我有以下卖家代码

#!/bin/sh
echo "hello"
echo "enter the salutation $abc"
read -r abc
if [ "$abc" = "1" ]
then
 echo "Hiiii"
elif [ "$abc" = "2" ]
then
echo "haaaaa"
fi
echo "enter name $xyz"
read -r xyz
if 
if [ "$xyz" = "1" ]
then
 echo "Chris"
elif [ "$xyz" = "2" ]
then
echo "Morris"
fi
echo "you had put salutation as" "$abc"
echo "you entered name as " "$xyz"

我需要最后的打印才能像

 you had put salutation as Hii
 you entered name as chris

我得到的是

 you had put salutation as 1
 you entered name as 1

  

有任何帮助吗？我是否需要在if elif中提及最终声明   声明？

Answer 1

问题在于你的echo语句：

echo "Hiiii"
echo "haaaaa"
echo "Chris"
echo "Morris"

您只是打印字符串，但不将其存储在可以显示为预期输出的变量中：

echo "you had put salutation as" "$abc"
echo "you entered name as " "$xyz"

您输入的abc和xyz中存储的值将为1和1。使用变量存储值并在需要时显示它们。比如，用以下内容替换echo：

disp_sal="Hiiii" disp_sal="haaaaa"

disp_name="Chris" disp_name="Morris"

也

echo "you had put salutation as" "$disp_sal"
echo "you entered name as " "$disp_name"

Answer 2

试试这个;

#!/bin/sh
    echo "hello"
    echo "enter the salutation $abc"

    read -r abc

    if [ "$abc" = "1" ]
    then
        x="Hiiii"
    elif [ "$abc" = "2" ]
    then
        x="haaaaa"
    fi

    echo "enter name $xyz"

    read -r xyz

    if [ "$xyz" = "1" ]
    then
         y="Chris"
    elif [ "$xyz" = "2" ]
    then
         y="Morris"
    fi
    echo "you had put salutation as" "$x"
    echo "you entered name as " "$y"

Answer 3

我会用：

#!/bin/bash

PS3="Enter the salutation>"
select abc in Hiii Haaa; do
    [[ "$abc" ]] && break
done

PS3="Enter name>"
select xyz in Chris Morris; do
    [[ "$xyz" ]] && break
done

echo "you had put salutation as" "$abc"
echo "you entered name as " "$xyz"