Question

我正在开发一个Web应用程序，其中我有一个带有表单的Index.jsp，用于将文件上传到servlet：

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1" 
  import="com.uteva.AppWebNieve.ProcesadoExcel"
   pageEncoding="ISO-8859-1"%>
 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
   "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
  <html xmlns="http://www.w3.org/1999/xhtml" 
     xmlns:f="http://java.sun.com/jsf/core" 
    xmlns:h="http://java.sun.com/jsf/html" 
      xmlns:ui="http://java.sun.com/jsf/facelets" lang="es" xml:lang="es">

      <head>
         <meta http-equiv="Content-Type" content="text/html; charset=ISO-
        8859-1">
          <title>AppWebInformesNieve</title>
       </meta>
  </head>
     <body>


      <form action="upload" method="post" enctype="multipart/form-data">   
         <input type="file" name="file" />
           <input value="Subir Excel" type="submit" />
        </form>

          </body>
       </html>

然后我用我的java类正确上传文件：

            @Override
      protected void doPost(HttpServletRequest 
              request,HttpServletResponse response) throws ServletException, 
           IOException{
         //***************AQUI MANEJAMOS LA SUBIDA DEL FICHERO LINCES DE INCIDENCIAS***********************
        // Get the file location where it would be stored.
          //String filePath = getServletContext().getInitParameter("file-upload");            
          boolean isMultipart;      
          int maxFileSize = 10000 * 1024;
          int maxMemSize = 1000 * 1024;
          File file ;
         // Check that we have a file upload request
          isMultipart = ServletFileUpload.isMultipartContent(request);
          response.setContentType("text/html");
          java.io.PrintWriter out = response.getWriter( );
          if( !isMultipart ){   //No se ha podido subir el fichero
             /*out.println("<html>");
             out.println("<head>");
             out.println("<title>Servlet upload</title>");  
             out.println("</head>");
             out.println("<body>");
             out.println("<p>No file uploaded</p>"); 
             out.println("</body>");
             out.println("</html>");*/
             return;
          }
          DiskFileItemFactory factory = new DiskFileItemFactory();
          // maximum size that will be stored in memory
          factory.setSizeThreshold(maxMemSize);
          // Location to save data that is larger than maxMemSize.
          factory.setRepository(new File("c:\\temp"));

          // Create a new file upload handler
          ServletFileUpload upload = new ServletFileUpload(factory);
          // maximum file size to be uploaded.
          upload.setSizeMax( maxFileSize );

          try{ 
          // Parse the request to get file items.
          List fileItems = upload.parseRequest(request);

          // Process the uploaded file items
          Iterator i = fileItems.iterator();

          out.println("<html>");
          out.println("<head>");
          out.println("<title>Servlet upload</title>");           
          out.println("</head>");
          out.println("<body>");
          while ( i.hasNext () ) 
          {
             FileItem fi = (FileItem)i.next();
             if ( !fi.isFormField () )  
             {
                // Get the uploaded file parameters
                String fieldName = fi.getFieldName();
                String fileName = fi.getName();
                String contentType = fi.getContentType();
                boolean isInMemory = fi.isInMemory();
                long sizeInBytes = fi.getSize();
                // Write the file
                if( fileName.lastIndexOf("\\") >= 0 ){
                   file = new File( filename + 
                   fileName.substring( fileName.lastIndexOf("\\"))) ;
                }else{
                   file = new File( filename + 
                   fileName.substring(fileName.lastIndexOf("\\")+1)) ;
                }
                fi.write( file ) ;
                out.println("Uploaded Filename: " + fileName + "<br>");
                System.out.println("Fichero "+filename+" subido correctamente al servidor!!");
             }
          }
          out.println("</body>");
          out.println("</html>");
       }catch(Exception ex) {
           System.out.println(ex);
       }
       }

但是在上传之后，这打开了一个新的简单html，它是由out.println在以前的java方法中构建的......

重点是，我如何管理这个上传以保持相同的HTML知道文件是否已上传或不使用此文件做其他事情？我不能使用get方法上传文件并让表单操作空白...

或者，打开一个新的html，必须有另一种方法来制作比Java函数中使用out.println更复杂的html ....

感谢。

Answer 1

最后，我按照本教程使用AJAX解决了这个问题：http://www.programming-free.com/2013/06/ajax-file-upload-java-iframe.html

上传文件到servlet后如何管理html网页？

1 个答案: