Question

我试图了解我的SQL代码中发生无效标识符错误的位置。输出状态，＆＃34;命令行错误：9列：10＆＃34;这是＆＃34; on＆＃34;功能在＆＃34;加入＆＃34;功能。任何帮助将不胜感激。

这是我的代码：

select
   TO_CHAR(TRUNC("SITE_UPLOAD_DATA_UPLOAD_TIME", 'MM'), 'MON') as month,
   cast (avg("DATA_POINT_UPLOAD_DATA"."value") as int) as "PAST_VALUE" 
from
   "TEST"."DATA_POINT_UPLOAD_DATA",
   "TEST"."COMPONENT_UPLOAD_DATA" 
   join
      "TEST"."COMPONENT_DATA_POINT" 
      on "DATA_POINT_UPLOAD_DATA"."COMPONENT_DATA_POINT_ID" = "COMPONENT_DATA_POINT"."ID" 
where
   "COMPONENT_DATA_POINT"."NAME" = 'ready_go' 
   and "COMPONENT_UPLOAD_DATA"."SITE_UPLOAD_DATA_SITE_ID" = ('abc123')
   and "SITE_UPLOAD_DATA_UPLOAD_TIME" between TRUNC (ADD_MONTHS ('01-MAR-17', - 13), 'MM') and TRUNC (LAST_DAY (ADD_MONTHS ('31-MAR-17', - 1)) + 1) 
group by
   TRUNC("SITE_UPLOAD_DATA_UPLOAD_TIME", 'MM'),
   "COMPONENT_UPLOAD_DATA"."SITE_UPLOAD_DATA_SITE_ID" 
order by
   TRUNC("SITE_UPLOAD_DATA_UPLOAD_TIME", 'MM') desc;

Answer 1

正如我从您发布的查询中看到的那样，您应该有两个JOIN，而您只指定一个JOIN ON条件

from
   "TEST"."DATA_POINT_UPLOAD_DATA"
   JOIN "TEST"."COMPONENT_UPLOAD_DATA" ON <some_condition>
   join
      "TEST"."COMPONENT_DATA_POINT" 
      on "DATA_POINT_UPLOAD_DATA"."COMPONENT_DATA_POINT_ID" = "COMPONENT_DATA_POINT"."ID"

标识符无效？

1 个答案: