如何在django模型上获取重复保存文件的文件名?

时间:2017-04-19 00:00:28

标签: python django model views

当我上传一个名称相同的文件时,第二个文件上传的名称如下:

First file: file.txt
Second file: file1YlQx18.txt

我想在views.py上获取第二个文件的名称 因为当我通过方法POST获取文件名时我只有file.txt

我正在使用Django Rest Framework序列化程序

viewsets.py
from rest_framework import mixins
from rest_framework.viewsets import GenericViewSet


class CreateOnlyViewSet(mixins.CreateModelMixin, GenericViewSet):

    def pos_create(self, request):
        pass

    def dispatch(self, request, *args, **kwargs):
        r = super(CreateOnlyViewSet, self).dispatch(request, *args, **kwargs)

    if r.status_code == 200 or r.status_code == 201:
        return self.pos_create(request)


serializers.py
from rest_framework import serializers
from .models import MyModel

    class CareerSerializer(serializers.ModelSerializer):
        class Meta:
            model = MyModel
            fields = '__all__'

views.py
from rest_framework.views import APIView    
from models import  MyModel
from .serializers import MyModelSerializer
from .viewsets import CreateOnlyViewSet


   class MyModelViewSet(CreateOnlyViewSet):
        model = MyModel
        serializer_class = MyModelSerializer

    def pos_create(self, request):
        serialized = MymodelSerializer(data=request.POST)
        #get name of the second file

0 个答案:

没有答案