我需要拿一张桌子,其中包含偶数队伍的名称,并为那些比赛生成赛程表,即如果有4个队伍:team1,team2,team3和team4在表格中,那么结果表将如下所示
Team Team Round
-----------------------
team1 team2 1
team 3 team4 1
team1 team3 2
team2 team4 2
team1 team4 3
team2 team3 3
我需要使用T-SQL执行此操作。我尝试过使用Round Robin Tournament算法,但我不知道如何在T-SQL中实现它。
答案 0 :(得分:0)
看到没有其他人给出了这个答案,我想我可能会向您展示一种(可能效率低下)使用动态SQL执行此操作的方法:
DECLARE @SQL NVARCHAR(MAX) = N'';
SELECT TOP (SELECT CASE COUNT(*) % 2 WHEN 1 THEN COUNT(*) ELSE COUNT(*) - 1 END FROM dbo.Teams) @SQL += N' UNION ALL
SELECT *
FROM
(
SELECT TOP (SELECT COUNT(*) / 2 FROM T)
Team,
RN,
RoundNum = ' + CAST(N AS NVARCHAR(3)) + N',
Match = ROW_NUMBER() OVER (ORDER BY CASE WHEN RN = 1 THEN 0 ELSE 1 END, (RN + ' + CAST(N - 2 AS NVARCHAR(3)) + N') % (SELECT COUNT(*) FROM T)),
Slot = 1
FROM T
ORDER BY CASE WHEN RN = 1 THEN 0 ELSE 1 END, (RN + ' + CAST(N - 2 AS NVARCHAR(3)) + N') % (SELECT COUNT(*) FROM T)
UNION ALL
SELECT TOP (SELECT COUNT(*) / 2 FROM T)
Team,
RN,
RoundNum = ' + CAST(N AS NVARCHAR(3)) + N',
Match = ROW_NUMBER() OVER (ORDER BY CASE WHEN RN = 1 THEN 1 ELSE 0 END, (RN + ' + CAST(N - 2 AS NVARCHAR(3)) + N') % (SELECT COUNT(*) FROM T) DESC),
Slot = 2
FROM T
ORDER BY CASE WHEN RN = 1 THEN 1 ELSE 0 END, (RN + ' + CAST(N - 2 AS NVARCHAR(3)) + N') % (SELECT COUNT(*) FROM T) DESC
) AS T
'
FROM (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM sys.objects) T(N)
ORDER BY N;
SELECT @SQL = N'
WITH T AS
(
SELECT Team, RN = ROW_NUMBER() OVER (ORDER BY Team)
FROM dbo.Teams
UNION ALL
SELECT ''Bye'', COUNT(*) + 1
FROM dbo.Teams
HAVING COUNT(*) % 2 = 1
),
CTE2 AS
(
' + STUFF(@SQL, 1, 11, '') + N'
)
SELECT T1.RoundNum, T1.Match, Team1 = T1.Team, Team2 = T2.Team
FROM
(
SELECT *
FROM CTE2
WHERE Slot = 1
) AS T1 JOIN
(
SELECT *
FROM CTE2
WHERE Slot = 2
) AS T2
ON T2.RoundNum = T1.RoundNum
AND T2.Match = T1.Match;';
EXEC sp_executesql @SQL;
基本上,它通过生根1并将所有团队转移到1来完成你的wiki链接中描述的fix one of the contributors in the first or last column of the table
。对于奇数队,它会增加一个“再见”对手。它只是在表中循环N或N-1次(取决于是否有偶数或奇数的团队)。