Question

data_set = ["This is cool jacket","I have two white shirts","I need black leather jacket", "I have five half shirts"]
shirt_list = []
jacket_list = []
def parse_data(clothes):
 for i in clothes:
   if "Jacket" in data_set:
     jacket_list.append(i)
   elif "shirt" in data_set:
     shirt_list.append(i)
   else:
     pass
 return shirt_list,jacket_list
print(parse_data(data_set))

我需要对特定字符串中的数据进行排序和收集，以便在我需要的代码中将夹克字符串打印在Jacket_list中，类似于衬衫。我尝试使用此代码不起作用。

Answer 1

快速解决您的问题是：

data_set = ["This is cool jacket","I have two white shirts","I need black leather jacket", "I have five half shirts"]
shirt_list = []
jacket_list = []
def parse_data(clothes):
 for i in clothes:
   if "jacket" in i:
     jacket_list.append(i)
   elif "shirt" in i:
     shirt_list.append(i)
   else:
     pass
 return shirt_list,jacket_list
print(parse_data(data_set))

原因是你试图查看总列表，而是查看每个i

然后我会将支票更改为更多通用支票，如下所示：

if "JACKET" in i.upper():
     jacket_list.append(i)
   elif "SHIRT" in i.upper():
     shirt_list.append(i)

这将有助于消除列表中更改的可能性

修改

如果您还想检查黑色，可以这样做：

for i in clothes: if "jacket" in i: if "black" in i: jacket_list.append(i) elif "shirt" in i: if "black" in i: shirt_list.append(i) else: pass

所有它正在做的是在里面添加一个额外的if语句，可能是更多的代码，但我认为它更容易阅读。

如果你想在同一个if语句中使用它，只需添加：

if "jacket" in i and "black" in i:

查找和排序字符串

1 个答案: