如果一个字段具有整数值以及php / mysql中的文本，如何显示数据？

Question

代码：

<?php
if($affiliated == '')
{
    echo $affiliated;
}
else
{
    $sql = "select * from all_university where university_id = '$affiliated'";
    $result = mysqli_query($link,$sql);
    while ($row = mysqli_fetch_array($result)) 
    {
        $short_name = $row['short_name'];
    }
}

＆GT;

在我的数据库表中，其字段名称是附属的，并且在不同的行中具有两个不同的值，其中一行具有＆＃39;整数＆＃39;价值和另一个有＆＃39;文本＆＃39;值。我想显示不同的值，即如果$ affiliated具有整数值，则打印整数其他打印文本。那么，我该如何解决这个问题呢？

谢谢

Answer 1

首先，您需要检查$affiliated是否numeric并在每行检查我的评论

//check for integer
    if (is_numeric($affiliated)) {
        //condition for integer
        //  any number multiply by 1 equal to that number
        $where = " WHERE concat('',university_id * 1) = university_id";
    } else {
        //condition for text
        $where = " WHERE concat('',university_id * 1) != university_id";// here use not equal to condition
    }
    $sql = "select * from all_university" . $where;// pass $where accouding to avove condition
    $result = mysqli_query($link, $sql);
    while ($row = mysqli_fetch_array($result)) {
        $short_name = $row['short_name'];
    }