我在Drupal 8中有多个值图像字段,我想在Controller中为树枝模板中的输出准备值。
这很简单(好吧,如果我们可以称之为非常复杂的"让我们在OOP中做所有事情 - 尽管它是无用的" Drupal 8简单的方法)单值字段:
$nids = \Drupal::entityQuery('node')->condition('type', 'zbornik_a_foto')->execute();
$nodes = Node::loadMultiple($nids);
$data = array();
foreach ($nodes as $node) {
$data[] = array(
'rocnik' => $node->get('field_rok')->getValue(),
'miesto' => $node->get('field_miesto_konania')->getValue(),
'fotografie' => $node->get('field_zbornik')->getValue(),
'foto' => $node->get('field_fotografie')->getValue(),
);
}
return array(
'#theme' => 'riadky_zazili',
'#data' => $data,
'#title' => 'Zažili sme',
);
但是,field_fotografie
值是多个值字段,我想在$data
数组中获取所有图像的URI。有人知道吗?理想情况下,不到10行无用的OOP jibber-jabber。感谢。
答案 0 :(得分:5)
尝试这样,它可能对你有用。
$data = array();
foreach($nodes as $node) {
$photo = array();
foreach($node->get('field_image')->getValue() as $file){
$fid = $file['target_id']; // get file fid;
$photo[] = \Drupal\file\Entity\File::load($fid)->getFileUri();
}
$data[] = array(
'rocnik' => $node->get('field_rok')->getValue(),
'miesto' => $node->get('field_miesto_konania')->getValue(),
'fotografie' => $node->get('field_zbornik')->getValue(),
'foto' => $photo,
);
}
答案 1 :(得分:0)
$nids = \Drupal::entityQuery('node')->condition('type', 'zbornik_a_foto')->execute();
$nodes = Node::loadMultiple($nids);
$data = array();
foreach ($nodes as $node) {
$fotoValues = $node->get('field_fotografie')->getValue();
$myvalues = array();
foreach($fotoValues as $val){
$myvalues[] = $val["value"];
}
$data[] = array(
'rocnik' => $node->get('field_rok')->getValue(),
'miesto' => $node->get('field_miesto_konania')->getValue(),
'fotografie' => $node->get('field_zbornik')->getValue(),
'foto' => $myvalues,
);
}
return array(
'#theme' => 'riadky_zazili',
'#data' => $data,
'#title' => 'Zažili sme',
);
希望这会对你有所帮助 感谢