涉及多个表Oracle,PL / SQL的触发器

时间:2017-04-12 23:21:47

标签: sql oracle plsql

我是SQL的新手,我正试图找出触发器。我需要编写一个涉及3个表的触发器,不要担心它只是由其中一个表触发...

CREATE TABLE CUSTOMERS 
(CUSTID CHAR(8) constraint customers_pk primary key, 
CREDITSCORE NUMBER(5,2)

CREATE TABLE LOANDETAILS 
(LOANNO VARCHAR2(11) primary key, 
CUSTID CHAR(8),  
LOANSTATUSCODE NUMBER(3,0), 
RATE NUMBER(5,2), 

CREATE TABLE SCORECONVERSIONCHART 
(SCOREBAND VARCHAR2(1) constraint scorecc_pk primary key, 
MINSCORE NUMBER(3,0), 
MAXSCORE NUMBER(3,0), 
BASERATEADJUSTMENT NUMBER(4,2)
);

因此,当更新客户表中的信用评分(信用核心)时,我想查看贷款详细信息表中的贷款类型(LOANTYPE)。如果贷款类型为1或2,我想更新贷款明细表中的贷款利率。通过查看分数转换图表中自定义信用评分下降的位置(客户表中的信用核心)来更新贷款利率 - 如果它位于转换图表中的给定最小和最大分数之间,则将适当的基础调整添加到基础率为3%。

我不清楚如何让所有这些表在触发器中进行交互,

如果有人能用简单的语言帮助我,或者给我一个很好的资源,我会很感激。

2 个答案:

答案 0 :(得分:2)

以下示例可能为您提供一个起点 如果贷款类型属于可调整类型,则此触发器将通过LOANDETAILS中的转换有条件地更新SCORECONVERSIONCHART,仅当信用评分更新时才会更新。

首先,添加一些测试数据:

INSERT INTO CUSTOMERS VALUES ('00000000','Frodo','Baggins',null,null,null,'frodo@hobbiton.com',123,750);
INSERT INTO CUSTOMERS VALUES ('00000001','Chewbacca','?',null,null,null,'chewie@hoth.com',456,775);


INSERT INTO LOANDETAILS VALUES ('A',NULL,'00000000','1',NULL,NULL,7.2,NULL,NULL);
INSERT INTO LOANDETAILS VALUES ('B',NULL,'00000001','3',NULL,NULL,4.2,NULL,NULL);

INSERT INTO SCORECONVERSIONCHART VALUES ('X',500,599,22);
INSERT INTO SCORECONVERSIONCHART VALUES ('Y',600,699,3);
INSERT INTO SCORECONVERSIONCHART VALUES ('Z',700,799,1);
COMMIT;

然后创建TRIGGER 编辑原始示例假定每个客户只有一笔贷款。更新为每位客户处理多笔贷款。

CREATE OR REPLACE TRIGGER Q2
AFTER UPDATE OF CREDITSCORE
  ON CUSTOMERS
FOR EACH ROW
  DECLARE
    V_LOAN_TYPE NUMBER;
  BEGIN
      UPDATE LOANDETAILS
      SET RATE = (SELECT SCORECONVERSIONCHART.BASERATEADJUSTMENT + 3
                  FROM SCORECONVERSIONCHART
                  WHERE :NEW.CREDITSCORE BETWEEN SCORECONVERSIONCHART.MINSCORE
                  AND SCORECONVERSIONCHART.MAXSCORE)
      WHERE LOANDETAILS.CUSTID = :NEW.CUSTID
      AND LOANDETAILS.LOANTYPE IN ('1','2');
END;
/

然后,测试一下:

SELECT CUSTID, LOANTYPE, RATE FROM LOANDETAILS;
CUSTID    LOANTYPE  RATE  
00000000  1         7.2   
00000001  3         4.2   

然后,更新非信用评分属性:

UPDATE CUSTOMERS SET STATE = 'WI';
SELECT CUSTID, LOANTYPE, RATE FROM LOANDETAILS;
CUSTID    LOANTYPE  RATE  
00000000  1         7.2   
00000001  3         4.2   

然后更新信用评分。佛罗多的贷款变动(他的贷款类型是合格的)为3%+分数转换图调整为3%,但是Chewie's根本不动。

UPDATE CUSTOMERS SET CREDITSCORE = 600;
SELECT CUSTID, LOANTYPE, RATE FROM LOANDETAILS;
CUSTID    LOANTYPE  RATE  
00000000  1         6     
00000001  3         4.2   

如果贷款类型是数字,我建议将其记录为数字。

答案 1 :(得分:0)

您可以执行以下操作。

    CREATE OR REPLACE TRIGGER trig
        AFTER UPDATE OF CREDITSCORE 
        ON CUSTOMERS
        FOR EACH ROW
        DECLARE
        temp_RATE LOANDETAILS.RATE%type
        temp_adj  SCORECONVERSIONCHART.BASERATEADJUSTMENT%type;
        BEGIN
        UPDATE LOANDETAILS
        SET RATE = RATE + 0.03* ( select s.BASERATEADJUSTMENT from customer c join loandetails l on c.custid=l.custid cross join SCORECONVERSIONCHART s where new.crediscore between s.minscore and s.maxscore and l.LOANTYPE in (1,2) and c.custid=new.custid)
WHERE CUSTID= ( select c.custid from customer c join loandetails l on c.custid=l.custid cross join SCORECONVERSIONCHART s where new.crediscore between s.minscore and s.maxscore and l.LOANTYPE in (1,2) and c.custid=new.custid)

        END IF;
        END;
        /

现在,通过以上子查询,您将获得符合条件的客户的基础。您可以根据您的要求更改该费率。