Question

我正在为项目制作银行机器代码，每当您登录时都会出错。正在执行此操作的代码部分是：

if(pincheck == pin){
                loggedin = true;
                pincheck = 0;
                do{
                    System.out.println("Welcome, " + name);
                    System.out.println("");
                    System.out.println("Your account balance is $" + balance);
                    System.out.println("");
                    System.out.println("Press 1 to deposit funds");
                    System.out.println("Press 2 to withdraw funds");
                    System.out.println("Press 3 to log out");
                    System.out.println("");
                    options = in.nextInt();

                    switch (options) {
                        case 1: System.out.println("How much would you like to deposit?");          // deposit
                                deposit = in.nextFloat();

                                balance = balance  + deposit;
                                deposit = 0;

                                System.out.println("You have deposited funds into your account.");  // withdraw
                                System.out.println("");
                            break;
                        case 2: System.out.println("How much would you like to withdraw?");
                                withdraw = in.nextFloat();

                                balance = balance - withdraw;
                                withdraw = 0;

                                System.out.println("You have removed funds from your account.");
                                System.out.println("");
                            break;
                        case 3: System.out.println("Logging out...");                               // log out
                                System.out.println("");
                                loggedin = false;
                            break;
                        default:System.out.println("Please enter a valid number");                  // Invalid number
                            break;
                    }
                }while(loggedin = true);

正在发生的事情是登录你需要输入一个数字，作为pincheck，如果它等于存在的引脚它将登录你。我可以登录但是当我按3退出时，它会打印退出并打印欢迎，整个事情再次开始。有谁可以指出我被困在哪里？

Answer 1

=是一个赋值运算符，因此您只需指定值（即设置loggedin=true），该值始终为true（因为您设置为true ）。

因此，您没有检查循环中的实际条件，因此您需要更正while条件，如下所示，它使用==运算符（用于计算条件表达式）：

while(loggedin == true); //use == for condition evaluation

陷入困境？

1 个答案: