Question

swift中的sorted func排序不正确。

未分类的对象

[＆＃34; 9＆＃34;，＆＃34; 7＆＃34;，＆＃34; 3＆＃34;，＆＃34; 8＆＃34;，＆＃34; 6＆＃34;，＆＃34; 2＆＃34;，＆＃34; 4＆＃34;，＆＃34; 10＆＃34;，＆＃34; 5＆＃34;]

排序对象

[＆＃34; 10＆＃34; ，＆＃34; 2＆＃34;，＆＃34; 3＆＃34;，＆＃34; 4＆＃34;，＆＃34 ; 5＆＃34;，＆＃34; 6＆＃34;，＆＃34; 7＆＃34;，＆＃34; 8＆＃34;，＆＃34; 9＆＃34;]

代码：

print("unsorted objects",students.map{($0 as! EX_STUDENT).roll_no!})

studentList = students.sorted{($0 as! EX_STUDENT).roll_no! < ($1 as! EX_STUDENT).roll_no!}

print("sorted objects",studentList.map{($0 as! EX_STUDENT).roll_no!})

为什么10是第0个指数？

Answer 1

您可以使用localizedStandardCompare以数字方式对字符串进行排序：

let numbers = ["9", "7", "3", "8", "6", "2", "4", "10", "5"]

let numericSort = numbers.sorted{$0.localizedStandardCompare($1) == .orderedAscending}

numericSort  // ["2", "3", "4", "5", "6", "7", "8", "9", "10"]

快速排序异常

1 个答案: