每月最多玩家按主持人分组

Question

我的MySQL查询有点麻烦

这是我的结构：

select * from servers group by host;


+-----+----------------------+---------+---------------------+
| id  | host                 | players | time                |
+-----+----------------------+---------+---------------------+
|   1 | 28.167.243.83:27035  |       3 | 2016-12-12 21:03:33 |
|   3 | 78.17.183.116:27015  |      10 | 2016-12-12 21:03:33 |
|  63 | 208.147.243.91:27025 |       1 | 2016-12-12 21:56:01 |
| 115 | 208.147.243.83:27035 |       2 | 2016-12-12 22:30:02 |
| 118 | 206.147.243.83:27035 |       2 | 2016-12-12 22:32:02 |
| 121 | 204.147.243.83:27035 |       2 | 2016-12-12 22:34:01 |
| 124 | 203.147.243.83:27035 |       2 | 2016-12-12 22:36:01 |
| 127 | 202.147.243.83:27035 |       2 | 2016-12-12 22:38:01 |
| 130 | 201.147.243.83:27035 |       2 | 2016-12-12 22:40:01 |
| 133 | 208.147.243.83:27035 |       2 | 2016-12-12 22:42:02 |
+-----+----------------------+---------+---------------------+

结果一直在进行，因为每个主机每5分钟就有一个新条目。

我希望它看起来像这样：

除了第二列应该如下：

unique date;max players on that unique date

用逗号分隔每个唯一的日期到最大玩家设置

如何通过查询实现此目的？

屏幕截图查询：

SELECT host, TRIM(TRAILING ',' FROM GROUP_CONCAT(DISTINCT CONCAT(UNIX_TIMESTAMP(`time`) * 1000, ',', players) ORDER BY `time` ASC SEPARATOR ';')) AS datapoints FROM servers where `time` between date_sub(now(),INTERVAL 8 WEEK) and now() GROUP BY `host`

SQL小提琴：http://sqlfiddle.com/#!9/a1350d

Answer 1

试试这个：

SELECT
    `host`,
    GROUP_CONCAT(CONCAT(`day`,';',`max_players`)) as `info`
FROM (SELECT
        `host`,
        DATE_FORMAT(`time`,'%Y-%m-%d') as `day`,
        MAX(`players`) as `max_players`
    FROM `so_test_servers`
    GROUP BY `host`, `day`) as A
GROUP BY `host`

Answer 2

如果您希望用逗号连接的列，您可以编写GROUP BY查询并将其包装到另一个查询中，例如：

SELECT a.host, CONCAT(a.`date`, ';', a.max_players)
FROM (
 SELECT 
     `host`,
     DATE_FORMAT(`time`,'%Y-%m-%d') as `date`,
     MAX(`players`) as 'max_players'
 FROM servers
 GROUP BY host, `date`
) a;