I have thousands of objects in MongoDB. And I have a field called "Insert_Date" which String format:"DD-Month(eg.JUN)-YYYY hh:mm". I would like to convert it to Date or ISODate using mongo shell I've tried this one but it showed error "invalid ISO date"
db.collection.find().forEach(function(doc) {
doc.Insert_Date=new ISODate(doc.Insert_Date);
db.collection.save(doc);
})
Is there another way to convert it may be using regex? Any help would be appriciated.
答案 0 :(得分:0)
这是使用“01-JUN-2009 00:00”作为日期值的一种方法。
首先,解析出时间值:
db.dates.aggregate([
{
$project : {
day: { $substr: [ "$Date_Time", 0, 2 ] },
month: { $substr: [ "$Date_Time", 3, 3 ] },
year: { $substr: [ "$Date_Time", 7, 4 ] },
hour: { $substr: [ "$Date_Time", 12, 2 ] },
minute: { $substr: [ "$Date_Time", 15, 2 ] }
}
},
{ $out : "dates" }
]);
然后,将月份MMM字符串转换为MM数字,就像您在评论中提到的那样。 您需要使用版本3.4或更高版本才能使用switch语句:
db.dates.aggregate( [
{
$project: {
"day": "$day",
"year": "$year",
"hour": "$hour",
"minute": "$minute",
"month" :
{
$switch: {
branches: [
{ case: { $eq: [ "$month", "JAN" ] }, then: "01" },
{ case: { $eq: [ "$month", "FEB" ] }, then: "02" },
{ case: { $eq: [ "$month", "MAR" ] }, then: "03" },
{ case: { $eq: [ "$month", "APR" ] }, then: "04" },
{ case: { $eq: [ "$month", "MAY" ] }, then: "05" },
{ case: { $eq: [ "$month", "JUN" ] }, then: "06" },
{ case: { $eq: [ "$month", "JUL" ] }, then: "07" },
{ case: { $eq: [ "$month", "AUG" ] }, then: "08" },
{ case: { $eq: [ "$month", "SEP" ] }, then: "09" },
{ case: { $eq: [ "$month", "OCT" ] }, then: "10" },
{ case: { $eq: [ "$month", "NOV" ] }, then: "11" },
{ case: { $eq: [ "$month", "DEC" ] }, then: "12" }
]
}
}
}
},
{ $out : "dates" }
]);
然后,您可以创建MongoDB将其解释为日期的字符串:
db.dates.find().forEach(function(doc) {
db.dates.update({_id: doc._id},{$set : {"Date_Time": doc.year + '-' + doc.month + '-' + doc.day + 'T' + doc.hour + ':' + doc.minute}});
});
最后一步是通过将字符串传递给Date():
来构造ISODatedb.dates.find().forEach(function(doc) {
doc.Date_Time=new Date(doc.Date_Time);
db.dates.save(doc);
})