我坚持了一段时间,我不知道如何解决这个问题。问题是我的SQL查询没有从javaFX textfield和passwordfield获取输入(我正在构建一个登录窗口)。 如果我手动输入值而不是从文本字段中获取它们,程序工作正常,否则当您按下登录按钮时没有任何反应。问题出现在以下行,当然没有错误消息:
preparedStatement.setString(1,txtUserName.getText());
preparedStatement.setString(2,txtPassword.getText());
以下是完整代码:
public class LoginWindow implements Initializable{
@FXML
private TextField txtUserName;
@FXML
private PasswordField txtPassword;
@FXML
private Button btnLogin;
Connection connection = null;
PreparedStatement preparedStatement = null;
ResultSet resultSet = null;
// Setting the login button.
@FXML
private void setBtnLogin(ActionEvent event) {
try {
connection = DBUtilities.getConnection();
String sqlQuery = "SELECT * FROM user_login_details WHERE User_Name = ? AND User_Password = ?";
preparedStatement = connection.prepareStatement(sqlQuery);
preparedStatement.setString(1,txtUserName.getText());
preparedStatement.setString(2,txtPassword.getText());
resultSet = preparedStatement.executeQuery();
if(resultSet.next()) {
DBUtilities.showInforMsg("Logged in:", "You have logged in!");
} else {
DBUtilities.showErrorMsg("Error:", "Invalid username or password");
}
}catch (Exception exception) {
exception.printStackTrace();
}finally {
DBUtilities.closePreparedStatement(preparedStatement);
DBUtilities.closeResultSet(resultSet);
DBUtilities.closeConnection(connection);
}
}
@Override
public void initialize(URL location, ResourceBundle resources) {
btnLogin.setOnAction(this::setBtnLogin);
}
}
答案 0 :(得分:1)
非常感谢你。我根本没有给密码字段提供任何ID。
答案 1 :(得分:0)
您可以先尝试从输入字段打印字符串进行调试:
String username = txtUserName.getText();
String password = txtPassword.getText();
System.out.println("User name = " + username);
System.out.println("Password = " + password);
preparedStatement.setString(1, username);
preparedStatement.setString(2, password);
如果用户名和密码为null,请确保这些字段控制器与FXML文档绑定良好。