我有json需要测试一个包含utf16宽字符的字符串但是我收到以下错误消息:
\..\test\TestClass.cpp(617): error C2440: 'initializing' : cannot convert from 'const char [566]' to 'std::basic_string<_Elem,_Traits,_Ax>'
with
2> [
2> _Elem=wchar_t,
2> _Traits=std::char_traits<wchar_t>,
2> _Ax=std::allocator<wchar_t>
2> ]
2> No constructor could take the source type, or constructor overload resolution was ambiguous
这是我的json:
static std::wstring& BAD_JSON5_missingComma_multipleNewlines_Utf16MixedDosAndUnixLineEndings()
{
static std::wstring j =
"{\n" <=VS squigly says error on this line
"\"header\":{\n"
"\"version\":{\"major\":1,\"minor\":0,\"build\":0}\n"
"},\n"
"\"body\":{\n"
"\"string\":{\"type\":\"OurWideStringClass\",\"value\":\"foo\"},\n\n\n\n"
"\"int\":[\n"
"{\"type\":\"string\",\"value\":\"\\u9CE5\"},\n"
"{\"type\":\"Int\",\"value\":5678}\n"
"],\n"
"\"double\":{\"type\":\"Double\",\"value\":12.34},\n"
"\"path1\":[\n"
"{\n"
"\"string\":{\"type\":\"OurWideStringClass\",\"value\":\"bar\"},\r\n"
"\"int\":[\n"
"{\"type\":\"Int\"\"value\":7},\n"
"{\"type\":\"Int\",\"value\":11}\n"
"]\n"
"},\n"
"{\n"
"\"string\":{\"type\":\"OurWideStringClass\",\"value\":\"top\"},\n"
"\"int\":[\n"
"{\"type\":\"Int\",\"value\":13},\r\n"
"{\"type\":\"Int\",\"value\":41}\n"
"]\n"
"}\n"
"],\n"
"\"path2\":{\n"
"\"int\":{\"type\":\"Int\",\"value\":-1234},\n"
"\"double\":{\"type\":\"Double\",\"value\":-1.234}\r\n"
"}\n"
"}\n"
"}\n"; <=double clicking build error goes to this line
return j;
}
这就是它的使用方式
OurWideStringClass slxStJson5 = BAD_JSON5_missingComma_multipleNewlines_Utf16MixedDosAndUnixLineEndings();
std::wistringstream ssJsonMissingCommaUtf16Newlines(slxStJson5);
我以为我的json中的wchar_t覆盖了std :: wstring。有什么想法是什么问题?你可以在\ u9ce5中看到我的utf16角色。这是此测试的关键。
我查看了这个c2440但是没有看到他们在UDT决议中提到的内容。
我正在看它前面的这个which puts an L ,但是对于逃脱的c字符串,我不知道把L放在哪里。
答案 0 :(得分:1)
std::wstring
无法从"my string"
std::wstring
初始化,因此编译错误。
您可以从narrow string literal初始化L
- 其语法包括开头引号之前的 L"my string"
前缀,,例如L
。
当您使用字符串文字串联时,需要在所有字符串文字前加static std::wstring j =
L"{\n"
L"\"header\":{\n"
L"\"version\":{\"major\":1,\"minor\":0,\"build\":0}\n"
L"},\n"
...
,即:
{{1}}