Question

这是一个项目，包括从应用程序注册用户并在MySQL数据库中注册。这适用于Swift 2.3，但我想在Swift 3中实现它，我不知道如何解决它。

URLSESSIONS.shared.dataTask上的错误

代码：

else{

        let url = URL(string: "http://localhost/billpain/secure/register.php")!
        let request = NSMutableURLRequest(url: url)
        request.httpMethod = "POST"
        let body = "username=\(usernameTxt.text!.lowercased())&password=\(passwordTxt.text!)&email=\(emailTxt.text!)&fullname=\(firstnameTxt.text!)%20\(lastnameTxt.text!)"
        request.httpBody = body.data(using: String.Encoding.utf8)

        **URLSession.shared.dataTask(with: request, completionHandler: {(data:Data?, response:URLResponse?, error:NSError?) in**

            if error == nil {
                DispatchQueue.main.async(execute: {

                    do {
                        let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary

                        guard let parseJSON = json else {
                        print ("Error while parsing")
                            return
                        }
                       let id = parseJSON["id"]
                        if id != nil {

                            print(parseJSON)

                        }

                    } catch {
                        print("Caught an error: \(error)")
                    }

                })

            } else{
                print("error: \(error)")
            }

        }).resume()

Answer 1

let url = URL(string: "http://localhost/billpain/secure/register.php")!
var urlRequest = URLRequest(url: url)
urlRequest.httpMethod = "POST"
let body = "username=\(usernameTxt.text!.lowercased())&password=\(passwordTxt.text!)&email=\(emailTxt.text!)&fullname=\(firstnameTxt.text!)%20\(lastnameTxt.text!)"
urlRequest.httpBody = body.data(using: String.Encoding.utf8)

let task = URLSession.shared.dataTask(with: urlRequest) { (data, response, error) in
if let error = error {
    print("error:", error)
    return
}

do {
    guard let data = data else { return }
    guard let json = try JSONSerialization.jsonObject(with: data, options: []) as? [String: AnyObject] 
else { return }
    print("json:", json)
} catch {
    print("error:", error)
}
}task.resume()

将Swift 2.3转换为3错误：无法使用类型的参数列表调用dataTask

1 个答案: