我有一个用C#编写的ASP.NET网站。
在这个网站上,我需要根据用户的位置自动显示一个起始页面。
我可以根据用户的IP地址获取用户所在城市的名称吗?
答案 0 :(得分:38)
您需要基于IP地址的反向地理编码API ...例如the one from ipdata.co。我确信有很多选择。
但是,您可能希望允许用户覆盖此内容。例如,它们可能位于公司VPN上,使IP地址看起来像,就像在不同的国家/地区一样。
答案 1 :(得分:20)
使用http://ipinfo.io,如果每天发出超过1000个请求,则需要付费。
以下代码需要Json.NET包。
public static string GetUserCountryByIp(string ip)
{
IpInfo ipInfo = new IpInfo();
try
{
string info = new WebClient().DownloadString("http://ipinfo.io/" + ip);
ipInfo = JsonConvert.DeserializeObject<IpInfo>(info);
RegionInfo myRI1 = new RegionInfo(ipInfo.Country);
ipInfo.Country = myRI1.EnglishName;
}
catch (Exception)
{
ipInfo.Country = null;
}
return ipInfo.Country;
}
我使用的IpInfo类:
public class IpInfo
{
[JsonProperty("ip")]
public string Ip { get; set; }
[JsonProperty("hostname")]
public string Hostname { get; set; }
[JsonProperty("city")]
public string City { get; set; }
[JsonProperty("region")]
public string Region { get; set; }
[JsonProperty("country")]
public string Country { get; set; }
[JsonProperty("loc")]
public string Loc { get; set; }
[JsonProperty("org")]
public string Org { get; set; }
[JsonProperty("postal")]
public string Postal { get; set; }
}
答案 2 :(得分:13)
IPInfoDB有an API可以调用,以便根据IP地址查找位置。
对于“City Precision”,您可以这样称呼它(您需要注册才能获得免费的API密钥):
http://api.ipinfodb.com/v2/ip_query.php?key=<your_api_key>&ip=74.125.45.100&timezone=false
VB和C#中的an example显示了如何调用API。
答案 3 :(得分:12)
以下代码工作。
<强> Upadate 强>
因为我正在调用免费的API请求(json base)IpStack。
public static string CityStateCountByIp(string IP)
{
//var url = "http://freegeoip.net/json/" + IP;
//var url = "http://freegeoip.net/json/" + IP;
string url = "http://api.ipstack.com/" + IP + "?access_key=[KEY]";
var request = System.Net.WebRequest.Create(url);
using (WebResponse wrs = request.GetResponse())
using (Stream stream = wrs.GetResponseStream())
using (StreamReader reader = new StreamReader(stream))
{
string json = reader.ReadToEnd();
var obj = JObject.Parse(json);
string City = (string)obj["city"];
string Country = (string)obj["region_name"];
string CountryCode = (string)obj["country_code"];
return (CountryCode + " - " + Country +"," + City);
}
return "";
}
修改: 首先,http://freegeoip.net/现在是https://ipstack.com/(也许现在是付费服务)
答案 4 :(得分:6)
我尝试过使用http://ipinfo.io,这个JSON API完美运行。首先,您需要添加下面提到的命名空间:
using System.Linq;
using System.Web;
using System.Web.UI.WebControls;
using System.Net;
using System.IO;
using System.Xml;
using System.Collections.Specialized;
对于localhost,它将伪造数据为AU
。您可以尝试对IP进行硬编码并获得结果:
namespace WebApplication4
{
public partial class WebForm1 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
string VisitorsIPAddr = string.Empty;
//Users IP Address.
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
//To get the IP address of the machine and not the proxy
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;`enter code here`
}
string res = "http://ipinfo.io/" + VisitorsIPAddr + "/city";
string ipResponse = IPRequestHelper(res);
}
public string IPRequestHelper(string url)
{
string checkURL = url;
HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();
StreamReader responseStream = new StreamReader(objResponse.GetResponseStream());
string responseRead = responseStream.ReadToEnd();
responseRead = responseRead.Replace("\n", String.Empty);
responseStream.Close();
responseStream.Dispose();
return responseRead;
}
}
}
答案 5 :(得分:6)
我能够使用客户端IP地址和freegeoip.net API在ASP.NET MVC中实现这一点。 freegeoip.net是免费的,不需要任何许可。
以下是我使用的示例代码。
String UserIP = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (string.IsNullOrEmpty(UserIP))
{
UserIP = HttpContext.Current.Request.ServerVariables["REMOTE_ADDR"];
}
string url = "http://freegeoip.net/json/" + UserIP.ToString();
WebClient client = new WebClient();
string jsonstring = client.DownloadString(url);
dynamic dynObj = JsonConvert.DeserializeObject(jsonstring);
System.Web.HttpContext.Current.Session["UserCountryCode"] = dynObj.country_code;
您可以浏览this post了解更多详情。希望它有所帮助!
答案 6 :(得分:5)
您可能不得不使用外部API,其中大部分都要花钱。
我确实找到了这个,似乎是免费的:http://hostip.info/use.html
答案 7 :(得分:4)
您需要的是一个“地理IP数据库”。他们中的大多数都花了一些钱(尽管不是太贵),尤其是相当精确的钱。其中使用最广泛的是MaxMind's database。他们有一个相当不错的免费版本的IP到城市数据库,名为GeoLity City - 它有很多限制,但如果你可以应对那可能是你最好的选择,除非你有一些钱可供选择订阅更准确的产品。
而且,是的,他们do have a C# API to query geo-IP databases可用。
答案 8 :(得分:4)
static public string GetCountry()
{
return new WebClient().DownloadString("http://api.hostip.info/country.php");
}
用法:
Console.WriteLine(GetCountry()); // will return short code for your country
static public string GetInfo()
{
return new WebClient().DownloadString("http://api.hostip.info/get_json.php");
}
用法:
Console.WriteLine(GetInfo());
// Example:
// {
// "country_name":"COUNTRY NAME",
// "country_code":"COUNTRY CODE",
// "city":"City",
// "ip":"XX.XXX.XX.XXX"
// }
答案 9 :(得分:4)
使用以下网站的请求
以下是返回国家和国家代码的C#代码
public string GetCountryByIP(string ipAddress)
{
string strReturnVal;
string ipResponse = IPRequestHelper("http://ip-api.com/xml/" + ipAddress);
//return ipResponse;
XmlDocument ipInfoXML = new XmlDocument();
ipInfoXML.LoadXml(ipResponse);
XmlNodeList responseXML = ipInfoXML.GetElementsByTagName("query");
NameValueCollection dataXML = new NameValueCollection();
dataXML.Add(responseXML.Item(0).ChildNodes[2].InnerText, responseXML.Item(0).ChildNodes[2].Value);
strReturnVal = responseXML.Item(0).ChildNodes[1].InnerText.ToString(); // Contry
strReturnVal += "(" +
responseXML.Item(0).ChildNodes[2].InnerText.ToString() + ")"; // Contry Code
return strReturnVal;
}
以下是Helper请求网址。
public string IPRequestHelper(string url) {
HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();
StreamReader responseStream = new StreamReader(objResponse.GetResponseStream());
string responseRead = responseStream.ReadToEnd();
responseStream.Close();
responseStream.Dispose();
return responseRead;
}
答案 10 :(得分:2)
这对你来说是个很好的样本:
public class IpProperties
{
public string Status { get; set; }
public string Country { get; set; }
public string CountryCode { get; set; }
public string Region { get; set; }
public string RegionName { get; set; }
public string City { get; set; }
public string Zip { get; set; }
public string Lat { get; set; }
public string Lon { get; set; }
public string TimeZone { get; set; }
public string ISP { get; set; }
public string ORG { get; set; }
public string AS { get; set; }
public string Query { get; set; }
}
public string IPRequestHelper(string url)
{
HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();
StreamReader responseStream = new StreamReader(objResponse.GetResponseStream());
string responseRead = responseStream.ReadToEnd();
responseStream.Close();
responseStream.Dispose();
return responseRead;
}
public IpProperties GetCountryByIP(string ipAddress)
{
string ipResponse = IPRequestHelper("http://ip-api.com/xml/" + ipAddress);
using (TextReader sr = new StringReader(ipResponse))
{
using (System.Data.DataSet dataBase = new System.Data.DataSet())
{
IpProperties ipProperties = new IpProperties();
dataBase.ReadXml(sr);
ipProperties.Status = dataBase.Tables[0].Rows[0][0].ToString();
ipProperties.Country = dataBase.Tables[0].Rows[0][1].ToString();
ipProperties.CountryCode = dataBase.Tables[0].Rows[0][2].ToString();
ipProperties.Region = dataBase.Tables[0].Rows[0][3].ToString();
ipProperties.RegionName = dataBase.Tables[0].Rows[0][4].ToString();
ipProperties.City = dataBase.Tables[0].Rows[0][5].ToString();
ipProperties.Zip = dataBase.Tables[0].Rows[0][6].ToString();
ipProperties.Lat = dataBase.Tables[0].Rows[0][7].ToString();
ipProperties.Lon = dataBase.Tables[0].Rows[0][8].ToString();
ipProperties.TimeZone = dataBase.Tables[0].Rows[0][9].ToString();
ipProperties.ISP = dataBase.Tables[0].Rows[0][10].ToString();
ipProperties.ORG = dataBase.Tables[0].Rows[0][11].ToString();
ipProperties.AS = dataBase.Tables[0].Rows[0][12].ToString();
ipProperties.Query = dataBase.Tables[0].Rows[0][13].ToString();
return ipProperties;
}
}
}
并测试:
var ipResponse = GetCountryByIP("your ip address or domain name :)");
答案 11 :(得分:1)
使用API的替代方法是使用HTML 5位置导航器向浏览器查询用户位置。我正在寻找与主题问题类似的方法,但我发现HTML 5 Navigator对我的情况更好,更便宜。请考虑您的scinario可能会有所不同。 使用Html5获取用户位置非常简单:
function getLocation()
{
if (navigator.geolocation)
{
navigator.geolocation.getCurrentPosition(showPosition);
}
else
{
console.log("Geolocation is not supported by this browser.");
}
}
function showPosition(position)
{
console.log("Latitude: " + position.coords.latitude +
"<br>Longitude: " + position.coords.longitude);
}
上亲自试用
答案 12 :(得分:0)
public static string GetLocationIPAPI(string ipaddress)
{
try
{
IPDataIPAPI ipInfo = new IPDataIPAPI();
string strResponse = new WebClient().DownloadString("http://ip-api.com/json/" + ipaddress);
if (strResponse == null || strResponse == "") return "";
ipInfo = JsonConvert.DeserializeObject<IPDataIPAPI>(strResponse);
if (ipInfo == null || ipInfo.status.ToLower().Trim() == "fail") return "";
else return ipInfo.city + "; " + ipInfo.regionName + "; " + ipInfo.country + "; " + ipInfo.countryCode;
}
catch (Exception)
{
return "";
}
}
public class IPDataIPINFO
{
public string ip { get; set; }
public string city { get; set; }
public string region { get; set; }
public string country { get; set; }
public string loc { get; set; }
public string postal { get; set; }
public int org { get; set; }
}
=========================
public static string GetLocationIPINFO(string ipaddress)
{
try
{
IPDataIPINFO ipInfo = new IPDataIPINFO();
string strResponse = new WebClient().DownloadString("http://ipinfo.io/" + ipaddress);
if (strResponse == null || strResponse == "") return "";
ipInfo = JsonConvert.DeserializeObject<IPDataIPINFO>(strResponse);
if (ipInfo == null || ipInfo.ip == null || ipInfo.ip == "") return "";
else return ipInfo.city + "; " + ipInfo.region + "; " + ipInfo.country + "; " + ipInfo.postal;
}
catch (Exception)
{
return "";
}
}
public class IPDataIPAPI
{
public string status { get; set; }
public string country { get; set; }
public string countryCode { get; set; }
public string region { get; set; }
public string regionName { get; set; }
public string city { get; set; }
public string zip { get; set; }
public string lat { get; set; }
public string lon { get; set; }
public string timezone { get; set; }
public string isp { get; set; }
public string org { get; set; }
public string @as { get; set; }
public string query { get; set; }
}
=============================
private static string GetLocationIPSTACK(string ipaddress)
{
try
{
IPDataIPSTACK ipInfo = new IPDataIPSTACK();
string strResponse = new WebClient().DownloadString("http://api.ipstack.com/" + ipaddress + "?access_key=XX384X1XX028XX1X66XXX4X04XXXX98X");
if (strResponse == null || strResponse == "") return "";
ipInfo = JsonConvert.DeserializeObject<IPDataIPSTACK>(strResponse);
if (ipInfo == null || ipInfo.ip == null || ipInfo.ip == "") return "";
else return ipInfo.city + "; " + ipInfo.region_name + "; " + ipInfo.country_name + "; " + ipInfo.zip;
}
catch (Exception)
{
return "";
}
}
public class IPDataIPSTACK
{
public string ip { get; set; }
public int city { get; set; }
public string region_code { get; set; }
public string region_name { get; set; }
public string country_code { get; set; }
public string country_name { get; set; }
public string zip { get; set; }
}
答案 13 :(得分:-1)
你可以
using System.Net;
using System.IO;
using Newtonsoft.Json.Linq;
public ActionResult geoPlugin()
{
var url = "http://freegeoip.net/json/";
var request = System.Net.WebRequest.Create(url);
using (WebResponse wrs = request.GetResponse())
using (Stream stream = wrs.GetResponseStream())
using (StreamReader reader = new StreamReader(stream))
{
string json = reader.ReadToEnd();
var obj = JObject.Parse(json);
var City = (string)obj["city"];
// - For Country = (string)obj["region_name"];
//- For CountryCode = (string)obj["country_code"];
Session["CurrentRegionName"]= (string)obj["country_name"];
Session["CurrentRegion"] = (string)obj["country_code"];
}
return RedirectToAction("Index");
}