我档案的相关部分是:
82 0a 96 c9 82 0a 96 d3 00 66 13 08
我在mappedbytebuffer中打开文件并将位置设置为开头。然后我这样做:
MappedByteBuffer buffer = channel.map(FileChannel.MapMode.READ_ONLY, 0, channel.size());
...
buffer.position(packetInfos.get(idPacket).getStartPos());
//getting the time from the packet header
time = Math.addExact(Math.multiplyExact((long) buffer.order(ByteOrder.LITTLE_ENDIAN).getInt(), 1000), Math.floorDiv(buffer.order(ByteOrder.LITTLE_ENDIAN).getInt(), 1000));
//getting the source ip from the ip frame
buffer.position(packetInfos.get(idPacket).getStartPos() + PACKET_IPSOURCE_OFFS); // puts the buffers position at the part of the file shown above
source = byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get());
//getting the destination ip from the ip frame
destination = byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get());
byteToUnsigned方法只是:
public static int byteToUnsigned(byte b){
return b & 0xFF;
}
来源最终成为:" 130.10.150.211"什么时候应该是" 130.10.150.201"。 出于某种原因,get()方法在大多数情况下将缓冲区的位置增加1,但在第三次增加后增加5?正如您可能已经猜到的那样,我之后尝试解码目的地ip并且在" D3"之后开始阅读,从而导致" 0.102.19.8"
甚至在byteToUnsigned调用源之前,Ip是" -126.10.-106.-45"。
逐步调试此行后:
source = byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get()) + "." + byteToUnsigned(buffer.get());
观察buffer.position()和buffer.get(),我可以看到以下内容:
所以位置正确递增,但第72和第77之间的字节在某种程度上对缓冲区不可见?
Api明确指出:
public abstract byte get()
Relative get method. Reads the byte at this buffer's current position, and then increments the position.
我错过了什么?
答案 0 :(得分:-1)
原来我是一个巨大的白痴。我没注意到字节82 0a 96只重复了几个字节。这是我不小心放置缓冲区位置的地方。别担心,我感到很惭愧。