Question

如何将input.json转换为output.json？

我找到了Python flatten/unflatten 和Json flatten但不符合我的需要。

input.json

{
  "root": {
    "d3": {
      "Selections": [
        "d3.select",
        "d3.selectAll"
      ],
      "Transitions": [
        "d3.transition"
      ]
    }
  }
}

output.json

{
  "name": "root",
  "children": [{
    "name": "d3",
    "children": [{
      "name": "Selection",
      "children": [{
        "name": "d3.select"
      }, {
        "name": "d3.selectAll"
      }]
    }, {
      "name": "Transitions",
      "children": [{
        "name": "d3.transition"
      }]
    }]
  }]
}

Answer 1

我可以使用以下代码完成它。根据＆＃34;选择＆＃34;输出不完全是顺序。 && 34; Transitions＆＃34;和＆＃34; name＆＃34; vs＆＃34;孩子＆＃34;，但我对此很好。

Python代码：

id|start|end
2|1994-05-01|1996-11-04  
4|1979-07-18|  
5|2005-02-01|2009-09-17  
5|2010-10-01|2012-10-06

输出是（用#!/usr/bin/env python2 import json import sys def load_data(filename): with open(filename) as data_file: data = json.load(data_file) return data def json_pprint(json_obj): print json.dumps(json_obj, sort_keys=False, indent=2, separators=(',', ': ')) def flatten_list(mylist): result = [] for item in mylist: entry = {} entry["name"] = item result.append(entry) return result def smart_flatten(myobj): if isinstance(myobj, list): result_list = flatten_list(myobj); return result_list; if isinstance(myobj, dict): result_list = [] for key, value in myobj.iteritems(): r = {} r["name"] = key r["children"] = smart_flatten(value) result_list.append(r) return result_list; if __name__ == "__main__": data = load_data("input.json") ####data = load_data(sys.stdin) mydict = smart_flatten(data) json_pprint(mydict)包装结果）：

[]

变换json以不平坦的方式添加“children”

1 个答案: