Question

我的服务器上有两个IP地址在同一个物理接口上：

eth0     10.10.10.11
eth0:0   10.10.10.12

Client IP address: 20.30.40.99

问题是当扩展（在另一个子网中）尝试注册时，服务器通过IP 10.10.10.11接收请求，但它尝试通过IP 10.10.10.12响应（根据我对日志的解释），所以扩展名没有注册。

这是日志：

[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: = Looking for  Call ID: ODU1N2VlNDlkYjQ2NzJkNTU1NTI0ZDc4MWFjOGFhY2I. (Checking From) --From tag d979d256 --To-tag   
[Apr  3 08:10:19] DEBUG[1758] acl.c: For destination '20.30.40.99', our source address is '10.10.10.12'.
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: Setting SIP_TRANSPORT_UDP with address 10.10.10.12:5060
[Apr  3 08:10:19] DEBUG[1758] netsock2.c: Splitting '20.30.40.99:52607' into...
[Apr  3 08:10:19] DEBUG[1758] netsock2.c: ...host '20.30.40.99' and port '52607'.
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: Allocating new SIP dialog for ODU1N2VlNDlkYjQ2NzJkNTU1NTI0ZDc4MWFjOGFhY2I. - PUBLISH (No RTP)
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: **** Received PUBLISH (15) - Command in SIP PUBLISH
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: Trying to put 'SIP/2.0 489' onto UDP socket destined for 20.30.40.99:52607
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: SIP message could not be handled, bad request: ODU1N2VlNDlkYjQ2NzJkNTU1NTI0ZDc4MWFjOGFhY2I.                          
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: Destroying SIP dialog ODU1N2VlNDlkYjQ2NzJkNTU1NTI0ZDc4MWFjOGFhY2I.
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: = Looking for  Call ID: Y2M3MmEyMjU2YTkyYzQxODlhNjI5N2Y1Y2NiMjkyMjA. (Checking From) --From tag 1262b86c --To-tag   
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: **** Received REGISTER (2) - Command in SIP REGISTER
[Apr  3 08:10:19] DEBUG[1758] chan_sip.c: Ignoring SIP message because of retransmit (REGISTER Seqno 2491, ours 2491)
[Apr  3 08:10:19] DEBUG[1758] netsock2.c: Splitting '20.30.40.99:52607' into...
[Apr  3 08:10:19] DEBUG[1758] netsock2.c: ...host '20.30.40.99' and port '52607'.

如何使Asterisk响应10.10.10.11（eth0）IP，而不是10.10.10.12（eth0：0）？

Answer 1

Chan sip将选择第一个可用的地址。

你可以做到

1）转到PJSIP并使用不同的传输部分

2）启动两个星号，一个在另一个ip上，进行互连。

3）如果您只需要在一个ip上工作，请使用bind =，然后使用externip = directive。

星号，两个IP地址，相同的段，相同的物理接口

1 个答案: