所以我的表有一列U,列名为u_id。
filter_out = filter A BY s_id == (FOREACH u GENERATE u_id);
我基本上试图通过匹配u表中的每一行来过滤一个表。 因此,如果A(table1)中的s_id与第二个表中的u_id匹配,则将其过滤掉
我输入'u'expecting LEFT_PAREN
错误
-------------第二种方法----------------
还尝试过将你转换为元组
totuple = FOREACH u GENERATE TOTUPLE (u_id);
filter_out = filter A BY s_id in (totuple);
和错误A column needs to be projected from a relation for it to be used as a scalar
答案 0 :(得分:1)
相反,加入两个表。这样只会将表A中的记录与表U中的记录匹配。最后生成所需的列。
B = JOIN A BY s_id,U BY u_id;
C = FOREACH B GENERATE B.$0; -- Select the needed columns from the joined relation.
DUMP C;