Question

就像我如何创建它以便用户可以输入char数组的值？

这是我尝试制作它的尝试，但出现了语法错误：

    char [] bacteriaStrand = new char[9];
    String bacteria = bac.next();
    bacteriaStrand = bacteria;

到目前为止，这是我的整个代码：

import java.util.Scanner;
public class SodiknBrukDNAAnalysispt3v1
{
    public static void main(String[] args)
    {
        Scanner bac = new Scanner(System.in);
        char [] treatmentStrand = {'T','C','G','A','G','A','G','T','A','T','C','C','C','A','G'};
        char [] bacteriaStrand = new char[9];
        char [] splicedStrand = new char[treatmentStrand.length + bacteriaStrand.length];
        System.out.println("NIH Treatment Splicer v. 1");
        System.out.println(" ");
        System.out.print("Treatment Strand: ");
        for (int t = 0; t < treatmentStrand.length; t++)
        {
            System.out.print(treatmentStrand[t]);
        }
        System.out.println(" ");
        System.out.print("Bacterium Strand: ");
        String bacteria = bac.next();
        bacteriaStrand = bacteria;
        for (int b = 0; b < bacteriaStrand.length; b++)
        {
            System.out.print(bacteriaStrand[b]);
            if (bacteriaStrand[b] != 'A' || bacteriaStrand[b] !='C' || bacteriaStrand[b] !='T' || bacteriaStrand[b] !='G')
            {
                System.out.println("Error! You can only input capital A, C, T, and G.");
            }
        }
    }
}

Answer 1

您正在为Char []分配String，因此它的类型不匹配，要么将字符串赋值给String Array，要么bacteriaStrand=bacteria.toCharArray();将String bacteriaStrand转换为Char []细菌。或者尝试

for(int i=0;i<bacteriaStrand.length;i++){
bacteriaStrand[i]=bac.next().charAt(0);
}

Answer 2

如果您想要char[]（基元），可以使用返回char[]的方法。

<强>的src：

public static char[] toCharArray(String input){
        StringTokenizer stringTokenizer = new StringTokenizer(input, " ");
        char[] chars = new char[stringTokenizer.countTokens()];

        for (int i = 0; i < chars.length; i++)
            chars[i] = stringTokenizer.nextToken().charAt(0);

        return chars;
    }

<强>实现：

char[] bacteriaStrand = toCharArray(bacteria);

- 或 -

如果你的字符串没有分隔：

* *编辑

第二个例子可以通过调用String＃toCharArray（）来轻松实现，它返回字符串中字符的副本。 - Obicere

String string = "STRING";
char[] chars = string.toCharArray();

感谢

Answer 3

这是一个可行的解决方案。

使用上面的建议（toCharArray）。我还添加了allowedcharacters列表，以便于比较，并在处理之前确保长度为9。

您可能还想忽略案例。

bacteria.toUpperCase().toCharArray();

这将有助于

public class SodiknBrukDNAAnalysispt3v1 {
    public static void main(String[] args) {
        Scanner bac = new Scanner(System.in);
        char [] treatmentStrand = {'T','C','G','A','G','A','G','T','A','T','C','C','C','A','G'};
        char [] bacteriaStrand = new char[9];
        char [] splicedStrand = new char[treatmentStrand.length + bacteriaStrand.length];
        System.out.println("NIH Treatment Splicer v. 1");
        System.out.println(" ");
        System.out.print("Treatment Strand: ");
        for (int t = 0; t < treatmentStrand.length; t++)
        {
            System.out.print(treatmentStrand[t]);
        }
        System.out.println(" ");
        System.out.print("Bacterium Strand: ");
        String bacteria = bac.next();
        if (bacteria.length() != 9) {
            System.out.println("Error! You are expected to input 9 characters");
            return ;
        }
        bacteriaStrand = bacteria.toCharArray();
        List<Character> allowedCharacters = Arrays.asList('A', 'C', 'T', 'G');
        for (int b = 0; b < bacteriaStrand.length; b++) {
            System.out.print(bacteriaStrand[b]);
            if (!allowedCharacters.contains(bacteriaStrand[b])) {
                System.out.println("Error! You can only input capital A, C, T, and G.");
                return;
            }
        }
    }
}

如何为char数组制作扫描仪？

3 个答案: