Question

这是主要订单表的外观： -

|  Order_num   | Collection_Num |
+--------------+----------------+
|  20143045585 |   123456       |
|  20143045585 |   789012       |
|  20143045585 |   456897       |
|  20143758257 |   546465       |
+--------------+----------------+

这些是收藏： -

|    tops      |      bottom    |
+--------------+----------------+
|  353735      |   745758       |
|  123456      |   789012       |
|  456456      |   456897       |
|  323456      |   546465       |
+--------------+----------------+

期望的输出： -

|  Order_num   |
+--------------+
|  20143045585 |

此处订单编号20143045585具有来自表编号2中的同一行的顶部和底部（第二表中的每一行形成称为＆＃39; A Collection＆＃39;即1个顶部和相应的底部）的特定组合。我想知道什么 - 所有订单号都有一个顶部和一个相应的底部在＆＃39; Collection_num＆＃39;柱。任何人都可以帮助我使用SQL代码吗？

如果有任何不清楚的地方，请告诉我。

Answer 1

select Order_num
From table_1 as A
where exists
(select tops from table_2 as B where B.tops = A.Collection_num) 
AND
(select bottom from table2 as B where B.bottom = A.Collection_num)

Answer 2

我假设你只有第一个数据表，每个订单只能有两个相关的集合或更少。也许：

\\ bignumber[3] == '8'
bignumber[3] = 4
\\ bignumber[3] == '4'

Answer 3

您可以尝试使用子查询

select distinct order_num from #yourorder where collection_num 
    in (select tops from #yourcollections) 
    and order_num in
    ( select order_num from #yourorder where collection_num in
         (select bottom from #yourcollections) )

Answer 4

非常确定这样的事情对你有用。我只是在这里使用ctes来创建测试数据，以便可以查询它。

with Orders (OrderNum, CollectionNum) as
(
    select 20143045585, 123456 union all
    select 20143045585, 789012 union all
    select 20143045585, 456897 union all
    select 20143758257, 546465 
)
, Collections (CollectionID, tops, bottoms) as
(
    select 1, 353735, 745758 union all
    select 2, 123456, 789012 union all
    select 3, 456456, 456897 union all
    select 4, 323456, 546465
)

select o.OrderNum
    , t.tops
    , b.bottoms
from Orders o
join Collections t on t.tops = o.CollectionNum
join
(
    select o.OrderNum
        , b.bottoms
        , b.CollectionID
    from Orders o
    join Collections b on b.bottoms = o.CollectionNum
) b on b.CollectionID = t.CollectionID

Answer 5

以下是我使用的查询：

Select * 
From  (select A.Order_num, B.Coll_ID, B.Bottoms from Orders_table as A
        Join Collections_Table as B
         on A.Collection_num = B.Bottoms
       ) as C 
  join
      (select K.Order_num, M.Coll_ID, M.Tops from Orders_table as K
        Join Collections_Table as M
         on A.Collection_num = B.Tops
       ) as D 
  on C.Orders_B = D.Orders_Num AND C.Coll_ID = D.Coll_ID
)

如何获得订单编号，其中集合编号具有顶部和相应的底部？

5 个答案: