我的任务是在jsonObj中获取3个不同的颜色列表并将它们放入<ul>
。它们应该每次只出现一次,每秒一次。为了小提琴,我每隔5秒就把它放一次。
我还没有获得第二或第三个颜色列表,因为虽然我可以列出我的第一个颜色列表,但它们会在我为它们创建的listItem之外添加。它吐出的代码是:
var jsonObj = '{"one":["red","green","blue"], "two":["red","green","blue"], "three":["orange","purple","hotpink"]}',
object = JSON.parse(jsonObj),
cOne = object.one,
cTwo = object.two,
cThree = object.three,
i = 0,
timer;
$('body').append('<ul/>');
timer = setInterval(function() {
$.each(cOne, function() {
var list = $('body ul'),
listItem = $(list).append('<li>'),
html = $(listItem).append(cOne[i]);
if (i < cOne.length) {
i++;
$(cOne[i]).split("");
list.append(html);
} else if (i = cOne.length) {
i = 0;
}
});
}, 5 * 1000);
timer;
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
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也可在https://jsfiddle.net/ep76ba3u/
获取它的作用:
<ul>
<li></li>
"red"
<li></li>
"blue"
</ul>
应该是什么样的:
<ul>
<li>red</li>
<li>blue</li>
</ul>
我试过重新整理一切。我尝试过使用wrap,innerWrap。我尝试过使用text()和其他一些方法。我开始在凌晨3点和现在凌晨5点开始工作......大脑被炒了。任何想法如何让这种感动都值得赞赏。
答案 0 :(得分:1)
您无法附加部分HTML,这就是为什么$(list).append('<li>')
会立即关闭<li>
。
您不应该在循环中修改标记。它令人讨厌且无能为力。
查看代码的这种方法:
var jsonObj = '{"one":["red","green","blue"], "two":["red","green","blue"], "three":["orange","purple","hotpink"]}',
object = JSON.parse(jsonObj),
iteration = 0,
timer;
$('body').append('<div id=container>');
//a few utilities, because I don't want to repeat myself all over the place:
var string = value => value == null ? "" : String(value);
var wrapInNode = nodeName => value => `<${nodeName}>${ string(value) }</${nodeName}>`;
//here I create a few utility-methods that will build my markup:
var li = wrapInNode('li');
var ul = wrapInNode('ul');
var header = wrapInNode('h4');
timer = setInterval(function() {
//building the complete markup and adding it at once
var blocks = [],
//how many rows should I show in this iteration
numRowsLeft = ++iteration,
//getting this result is just a nice sideeffect of using `every()` instead of `forEach()`
//to short-curcuit the loop
done = Object.keys(object)
.every(function(key) {
//this line makes the title to be added with as a distinct iteration and not with the first item,
//check out what happens when you remove it
--numRowsLeft;
var rows = object[key]
//shorten the Array to numRowsLeft, if necessary
.slice(0, numRowsLeft)
//wrap each item in a li-node with my predefined utility-function
.map(li);
numRowsLeft -= rows.length;
//building the markup for this block
blocks.push(header(key) + ul(rows.join("")));
//here I'm short circuiting the loop. to stop processing the other keys on Object
return numRowsLeft > 0;
});
$('#container').html(blocks.join(""));
if (done) {
clearInterval(timer);
}
}, 1000);
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
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一直显示标题,只添加点数:
var jsonObj = '{"one":["red","green","blue"], "two":["red","green","blue"], "three":["orange","purple","hotpink"]}',
object = JSON.parse(jsonObj),
iteration = 0,
timer;
$('body').append('<div id=container>');
var string = value => value == null ? "" : String(value);
var wrapInNode = nodeName => value => `<${nodeName}>${ string(value) }</${nodeName}>`;
var li = wrapInNode('li');
var ul = wrapInNode('ul');
var header = wrapInNode('h4');
timer = setInterval(function() {
var numRowsLeft = ++iteration,
blocks = Object.keys(object)
.map(function(key) {
var rows = object[key]
.slice(0, numRowsLeft)
.map(li);
numRowsLeft -= rows.length;
return markup = header(key) + ul(rows.join(""));
});
$('#container').html(blocks.join(""));
// If I'd had room to show even more rows, then I' done
if (numRowsLeft > 0) {
clearInterval(timer);
}
}, 1000);
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
&#13;
答案 1 :(得分:0)
var jsonObj = '{"one":["red","green","blue"], "two":["red","green","blue"], "three":["orange","purple","hotpink"]}',
object = JSON.parse(jsonObj),
cOne = object.one,
cTwo = object.two,
cThree = object.three,
i = 0,
timer;
$('body').append('<ul>');
var i = 0;
timer = setInterval(function() {
if (i === cOne.length - 1) clearInterval(timer);
$('body ul').append('<li>');
$('body ul li').last().text(cOne[i]);
i++;
}, 1000);
答案 2 :(得分:0)
我觉得有必要提出一个答案,该答案应该通过缓存jQuery对象来表现更好,并处理对象及其中的每种颜色,为每种颜色点击DOM一次。
var jsonObj = '{"one":["red","green","blue"], "two":["red","cyan","darkblue"], "three":["orange","purple","hotpink"]}',
objects = JSON.parse(jsonObj);
// set timer values
var basetime = 1000;
var delaytime = basetime;
// cache the ul list
var myul = $('<ul/>').appendTo('body');
//process outer objects
$.each(objects, function(key, item) {
// process color array held in item
$.each(item, function(index, color) {
setTimeout(function() {
$('<li/>').text(color).css('color', color).appendTo(myul);
}, delaytime);
delaytime = delaytime + basetime;
});
});