我有这个:
fit <- train(Purchase ~ .,
data = training,
method = "lm",
trControl = fitControl)
我想要这个:
Id Store Situation Total
1 Store 1 Credit 10
2 Store 1 No credit 20
3 Store 3 Credit 50
4 Store 3 No credit 80
这可能吗?
感谢。
答案 0 :(得分:1)
这只是条件聚合:
select store,
sum(case when situation = 'Credit' then total else 0 end) as Credit,
sum(case when situation = 'No Credit' then total else 0 end) as NoCredit,
from t
group by store;
您还可以添加id
。这是一种适用于大多数数据库的方法:
select row_number() over (order by store) as id,
store,
sum(case when situation = 'Credit' then total else 0 end) as Credit,
sum(case when situation = 'No Credit' then total else 0 end) as NoCredit,
from t
group by store
order by store;