我收到错误未定义变量:con at line:
$filter_Result = mysqli_query($con,$query);
在这个PHP文件中:
<?php require_once('../Connections/conexion.php');
if(isset($_POST['search']))
{
echo "estoy filtrando";
$valueToSearch = $_POST['valueToSearch'];
// search in all table columns
// using concat mysql function
$query = "SELECT * FROM `tblusuario` WHERE CONCAT(`idUsuario`, `strEmail, `strNombre`) LIKE '%".$valueToSearch."%'";
$search_result = filterTable($query);
$totalRows_DatosConsulta = mysqli_num_rows($search_result);
}
else {
echo "estoy sin filtrar";
$query = "SELECT * FROM `tblusuario`";
$search_result = filterTable( $query );
$totalRows_DatosConsulta = mysqli_num_rows( $search_result );
}
function filterTable($query)
{
$filter_Result = mysqli_query($con,$query);
return $filter_Result;
}
?>
这是文件conexion.php,其中定义了变量$ con:
$hostname_con = "p:localhost";
$database_con = "ondemand";
$username_con = "root";
$password_con = "";
$con = mysqli_connect($hostname_con, $username_con, $password_con, $database_con);
mysqli_set_charset($con, 'utf8');
我已检查文件conexion.php是否被正确找到,并且已加载。
我无法找到错误的原因。
答案 0 :(得分:1)
你需要像这样使用它
function filterTable($query)
{
global $con;
$filter_Result = mysqli_query($con,$query);
return $filter_Result;
}
或者您可以在调用函数时传递$con
作为参数。
function filterTable($con, $query)
{
$filter_Result = mysqli_query($con,$query);
return $filter_Result;
}
这是由于PHP中的变量范围。
答案 1 :(得分:1)
function filterTable($con, $query)
{
$filter_Result = mysqli_query($con,$query);
return $filter_Result;
}