我已经集成了一个用于推送通知的信号库。我想在应用未运行时通过点击推送通知打开特定活动 我正在接收推送通知但是当我点击通知时,应用程序崩溃了。这是我的通知接收器代码
public class ExampleNotificationOpenedHandler implements OneSignal.NotificationOpenedHandler
{
Context context;
@Override
public void notificationOpened(OSNotificationOpenResult result) {
OSNotificationAction.ActionType actionType = result.action.type;
JSONObject data = result.notification.payload.additionalData;
String customKey;
if (data != null) {
customKey = data.optString("customkey", null);
if (customKey != null)
Log.e("OneSignalExample", "customkey set with value: " + customKey);
}
if (actionType == OSNotificationAction.ActionType.ActionTaken)
Log.i("OneSignalExample", "Button pressed with id: " + result.action.actionID);
Intent intent = new Intent(context, User_Detail.class);
intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT | Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(intent);
}
这是我的错误消息
Attempt to invoke virtual method 'java.lang.String android.content.Context.getPackageName()' on a null object reference
答案 0 :(得分:4)
我错过了在onReceivedMethod
之前在类中构建构造函数Context context2;
ExampleNotificationOpenedHandler(Context context) {
context2 = context;
}
@Override
public void notificationOpened(OSNotificationOpenResult result) {
OSNotificationAction.ActionType actionType = result.action.type;
JSONObject data = result.notification.payload.additionalData;
String customKey;
Intent intent = new Intent(context2,User_Detail.class);
intent.setFlags(Intent.FLAG_ACTIVITY_REORDER_TO_FRONT | Intent.FLAG_ACTIVITY_NEW_TASK);
context2.startActivity(intent);
if (data != null) {
customKey = data.optString("customkey", null);
if (customKey != null)
Log.e("OneSignalExample", "customkey set with value: " + customKey);
}
if (actionType == OSNotificationAction.ActionType.ActionTaken)
{
Log.i("OneSignalExample", "Button pressed with id: " + result.action.actionID);
}
并在Application类
中传递上下文 @Override
public void onCreate() {
super.onCreate();
mInstance = this;
OneSignal.startInit(this)
.setNotificationOpenedHandler(new ExampleNotificationOpenedHandler(this))
.init();
}
答案 1 :(得分:1)
这意味着context
变量为空。
如果您查看Intent的源代码并选择了construcor
public Intent(Context packageContext, Class<?> cls) {
mComponent = new ComponentName(packageContext, cls);
}
ComponentName
construcor
public ComponentName(Context pkg, String cls) {
if (cls == null) throw new NullPointerException("class name is null");
mPackage = pkg.getPackageName(); //here you get crash
mClass = cls;
}
您可以使用DI来提供上下文,例如Dagger2。
或实现应用程序类
public class DemoApp extends Application {
private static DemoApp instance;
@Override
public void onCreate() {
instance = this;
super.onCreate();
}
public static DemoApp getInstance() {
return instance;
}
}
在你的清单中
<application
android:name=".demo.DemoApp"