Question

我是以下字符串。

What is (Jim)'s gift (limit)? <=> Personname <=> Amount::Spent

在此行中，我想查找并打印(和)的开始和结束位置。

在我目前的代码中，我能够打印它，但问题是，它会多次打印（我确定这是因为while）。< / p>

我的代码如下。

    String line = "What is (Rakesh)'s gift (limit)? <=> Personname <=> Amount::Spent";
    if (line.contains("<=>")) {
        String[] example_split = line.split("<=>", 2);
        System.out.println("String is " + example_split[1]);
        if (example_split[0].length() > 1) {
            String[] example_entity = example_split[1].split("<=>");

            for (String splitStrings : example_entity) {
                int openParamCount = line.length() - line.replace("(", "").length();
                int closeParamCount = line.length() - line.replace("(", "").length();
                System.out.println(openParamCount + "\t" + closeParamCount);
                if (!(openParamCount == closeParamCount))
                    System.out.println("Paranthesis don't match for " + line);
                if (!(openParamCount == example_entity.length))
                    System.out.println(
                            "The entities provided and the words marked in paranthesis don't match for " + line);

                int entities_count = 0;
                int no_of_entities = example_entity.length;
                Set utterancesSet = new HashSet<>();
                int startPosition = 0;
                int endPosition = 0;
                while (entities_count < no_of_entities) {
                    List<String> matchList = new ArrayList<String>();
                    Pattern regex = Pattern.compile("\\((.*?)\\)");
                    Matcher regexMatcher = regex.matcher(line);
                    while (regexMatcher.find()) {
                        startPosition = regexMatcher.start() + 1;
                        endPosition = regexMatcher.start() - 1;

                        matchList.add(regexMatcher.group(1));
                        System.out.println("start position is " + startPosition + " end position is " + endPosition
                                + " Entity Type" + example_entity[entities_count]);
                    }
                    entities_count++;
                }
            }
        }
    }

预期产出：

String is  Personname <=> Amount::Spent
2   2
start position is 9 end position is 12 Entity Type Personname 
start position is 22 end position is 27 Entity Type Amount::Spent

当前输出

String is  Personname <=> Amount::Spent
2   2
start position is 9 end position is 12 Entity Type Personname 
start position is 22 end position is 27 Entity Type Personname 
start position is 9 end position is 12 Entity Type Amount::Spent
start position is 22 end position is 27 Entity Type Amount::Spent
2   2
start position is 9 end position is 12 Entity Type Personname 
start position is 22 end position is 27 Entity Type Personname 
start position is 9 end position is 12 Entity Type Amount::Spent
start position is 22 end position is 27 Entity Type Amount::Spent

请让我知道我哪里出错了，我该如何解决这个问题。

由于

Answer 1

您需要删除2个循环

“for（String splitStrings：example_entity）”
“while（entities_count＆lt; no_of_entities）”

    String line = "What is (Rakesh)'s gift (limit)? <=> Personname <=> Amount::Spent";
    if (line.contains("<=>")) {
        String[] example_split = line.split("<=>", 2);
        System.out.println("String is " + example_split[1]);
        if (example_split[0].length() > 1) {
            String[] example_entity = example_split[1].split("<=>");

            int openParamCount = line.length() - line.replace("(", "").length();
            int closeParamCount = line.length() - line.replace("(", "").length();
            System.out.println(openParamCount + "\t" + closeParamCount);
            if (!(openParamCount == closeParamCount))
                System.out.println("Paranthesis don't match for " + line);
            if (!(openParamCount == example_entity.length))
                System.out.println(
                        "The entities provided and the words marked in paranthesis don't match for " + line);

            int entities_count = 0;
            int startPosition;
            int endPosition = 0;
            List<String> matchList = new ArrayList<>();
            Pattern regex = Pattern.compile("\\((.*?)\\)");
            Matcher regexMatcher = regex.matcher(line);
            while (regexMatcher.find()) {
                startPosition = regexMatcher.start() + 1;
                endPosition = regexMatcher.start() - 1;

                matchList.add(regexMatcher.group(1));
                System.out.println("start position is " + startPosition + " end position is " + endPosition
                        + " Entity Type" + example_entity[entities_count]);
            }
            entities_count++;
        }
    }

您的代码虽然暗示括号将始终关闭，但它不允许内部循环的空间，例如

什么是（（吉姆）和（凯尔）的礼物（限制）？

不会返回正确的结果。但如果您希望以该形式输入，这只是一个问题。

在一行中捕获相似的单词

1 个答案: