Question

我有一个包含三个功能的程序。每个函数从不同的网页上抓取数据，将其保存到列表中，然后打印列表。

我在终端运行它，它可以工作。

我想将这些列表打印到一个网页上。

我可以打印一个功能，但我不知道如何将多个功能放入烧瓶中。

继承人的作品：

.py文件

from flask import Flask, render_template    
import bs4 as bs
import urllib.request

app = Flask(__name__)

@app.route('/')
def chinaAds():

    sauce = urllib.request.urlopen('http://www.eslcafe.com/jobs/china/').read()
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    dl = soup.dl
    chinaAds = []
    china = []

    for words in dl.find_all('a'):
        links = words.get('href')
        link_text = words.text

        if ('university' in link_text.lower()) or ('universities' in link_text.lower()) or ('college' in link_text.lower()) or ('colleges' in link_text.lower()):
            chinaAds.append([links, link_text])

    for ad in chinaAds:
        china.append(tuple(ad))
    return render_template("eslJobs.html", china=china)

这是我在.html文件中打印的方式

<ul class="list-group col-md-4" style="padding-left: 18px;">
{% for href, caption in china %}
  <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
{% endfor %}
</ul>

我要添加到.py文件
的东西

我要添加的两个函数与第一个只有不同变量的函数相同，它们从不同的网页中删除

def koreaJobs():
    sauce = urllib.request.urlopen('http://www.eslcafe.com/jobs/korea/').read()
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    dl = soup.dl
    koreaAds = []
    korea []

    for words in dl.find_all('a'):
        links = words.get('href')
        link_text = words.text

        if ('university' in link_text.lower()) or ('universities' in link_text.lower()) or ('college' in link_text.lower()) or ('colleges' in link_text.lower()):
            koreaAds.append([links, link_text])

    for ad in koreaAds:
        korea.append(tuple(ad))
    return render_template("eslJobs.html", korea=korea)

def intlJobs():
    sauce = urllib.request.urlopen('http://www.eslcafe.com/joblist/').read()
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    dl = soup.dl
    intlAds = []
    intl = []

    for words in dl.find_all('a'):
        links = words.get('href')
        link_text = words.text

        if ('university' in link_text.lower()) or ('universities' in link_text.lower()) or ('college' in link_text.lower()) or ('colleges' in link_text.lower()):
            intlAds.append([links, link_text])

    for ad in intlAds:
        intl.append(tuple(ad))
    return render_template("eslJobs.html", intl=intl)

我将在我的.html页面中的两个新列表中打印这些函数中的数据

Answer 1

这是一个简单的例子，一种方法是简化刮刀功能，使它们只返回列表，然后将参数添加到render_template()：

from flask import Flask, render_template
import bs4 as bs
import urllib.request

app = Flask(__name__)

def get_ads(url):
    """ This function returns a list of tuples. """
    terms = ['universit', 'college']
    sauce = urllib.request.urlopen(url).read()  #
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    ads = []
    for words in soup.dl.find_all('a'):
        links = words.get('href')
        link_text = words.text
        if any(x in link_text.lower() for x in terms):
            ads.append(tuple([links, link_text]))
    return ads

# call functions here when the app starts
china = get_ads('http://www.example.com/jobs/china/')
korea = get_ads('http://www.example.com/jobs/korea/')
jobs = get_ads('http://www.example.com/joblist/')

@app.route('/')
def index():
    # or call functions here each time a page is requested

    return render_template("index.html", china=china, korea=korea, jobs=jobs)

if __name__ == '__main__':
    app.run(debug=True)

的index.html

<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in china %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in korea %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in jobs %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>

Flask：一页，3个功能 - 只能获得1个功能打印到网页

1 个答案: