我正在尝试搜索目录结构,以及存在模式的所有实例的文件。我希望该文件位置记录在日志文件中,我可以查看后者。我查看了各种帖子,但我没有找到类似的例子。已审核的帖子包括:
以下是我用来回避文件夹结构的代码:
#Set variables for paths
$Results = "C:\Results"
$Source = "C:\Test\*"
$Destination = "C:\MyTest\"
#Create file name for each report with date and time of run
$ReportDate = (Get-Date).ToString("dd-MM-yyyy-hh-mm-ss")
$CustomPattern = Read-Host 'What pattern are you looing for?'
$CustomPatternLog = New-Item -itemType File -Path C:\Results -Name $("CustomerPattern_" + $ReportDate + ".txt")
$CustomPattern = foreach ($file in Get-ChildItem -Path $Destination -Recurse | Select-String -pattern $CustomPattern | Select-Object -Unique Path) {$file.path}
$CustomPattern > "$($Results)\$($CustomPatternLog)"
但是,此代码返回以下错误:
Get-ChildItem:指定的路径,文件名或两者都太长。 完全限定的文件名必须少于260个字符,并且 目录名称必须少于248个字符。在线:19 焦炭:36 + $ CustomPattern = foreach(Get-ChildItem中的$ file -Path $ Destination -Recurse | S ... + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo:ReadError:(C:\ Test \ Mor ... ofiles \ Customer:St ring)[Get-ChildItem], PathTooLongException + FullyQualifiedErrorId:DirIOError,Microsoft.PowerShell.Commands.GetChil dItemCommand
你有更好的方法做同样的操作吗?
答案 0 :(得分:2)
替换此
$CustomPatternLog = New-Item -itemType File -Path C:\Results -Name $("CustomerPattern_" + $ReportDate + ".txt")
$CustomPattern = foreach ($file in Get-ChildItem -Path $Destination -Recurse | Select-String -pattern $CustomPattern | Select-Object -Unique Path) {$file.path}
$CustomPattern > "$($Results)\$($CustomPatternLog)"
用这个
$files = Get-ChildItem -Path $Destination -Recurse
#in case you would need the path replace FullName with PsParentPath
$result = ($files | ?{$_.name -like "*$CustomPattern*"}).FullName
$result | out-file ($CustomPattern + "_" + $ReportDate + ".txt")
并且因为它的外壳你可以用一个衬垫
做同样的事情(Get-ChildItem -Path $Destination -Recurse | ?{$_.name -like "*$CustomPattern*"}).FullName | out-file ($CustomPattern + "_" + $ReportDate + ".txt")