答案 0 :(得分:1)
假设每个ID
都是唯一的,并且您的数据按Time
排序,其中Stage = Start
是每个ID
的第一行,Stage = End
是最后一行每个ID
的行,你可以使用:
Concatenate(Min([Time]) OVER ([ID]),"-",Max([Time]) over ([ID]))
<强>结果
+----+---------+---------+------+-----------------+
| ID | Stage | Action | Time | Time Difference |
+----+---------+---------+------+-----------------+
| 1 | Start | approve | A | A-F |
| 1 | Process | approve | B | A-F |
| 1 | Process | approve | C | A-F |
| 1 | Process | approve | D | A-F |
| 1 | Process | decline | E | A-F |
| 1 | End | approve | F | A-F |
| 2 | Start | approve | G | G-I |
| 2 | Process | decline | H | G-I |
| 2 | End | approve | I | G-I |
+----+---------+---------+------+-----------------+
如果您的数据尚未排序,则只需应用Rank()
即可解决此问题。如果是这种情况,请告诉我。
使用新数据进行编辑
<强>表达强>
Concatenate(Min(If((Upper([Stage])="START") and (Upper([Action])="APPROVE"),Max([Time]) OVER ([ID]))) OVER ([ID]),"-",Min(If((Upper([Stage])="END") and (Upper([Action])="APPROVE"),Max([Time]) OVER ([ID]))) OVER ([ID]))
<强>简化强>
Concatenate(Min(If((Upper([Stage])="START") and (Upper([Action])="APPROVE"),[Time])) OVER ([ID]),"-",Min(If((Upper([Stage])="END") and (Upper([Action])="APPROVE"),[Time])) OVER ([ID]))
<强>结果
+----+---------+---------+------+-----------------+
| ID | Stage | Action | Time | Time Difference |
+----+---------+---------+------+-----------------+
| 1 | On hold | decline | A | C-H |
| 1 | Start | decline | B | C-H |
| 1 | Start | approve | C | C-H |
| 1 | Process | DECLINE | D | C-H |
| 1 | Process | approve | E | C-H |
| 1 | Process | approve | F | C-H |
| 1 | End | decline | G | C-H |
| 1 | End | approve | H | C-H |
| 2 | Start | approve | I | I-K |
| 2 | Process | decline | J | I-K |
| 2 | End | approve | K | I-K |
+----+---------+---------+------+-----------------+