Question

我要做的是创建一个包含1000个左右条目的字符串数组。而不是做：

public void DefaultGeneric(View v) throws FileNotFoundException{
    Random rand = new Random();
    int i = rand.nextInt(4) + 0;
    int j = rand.nextInt(4) + 0;
    String[] SomeThingA = {"yep","okay","nope"};    //I need this array to be much much larger but want a better way of doing it.
    String[] SomeThingB = {"test","test1","test2"}; //I need this array to be much much larger but want a better way of doing it.

    Toast.makeText(getBaseContext(), SomeThingA[i]+SomeThingB[j], Toast.LENGTH_LONG ).show();

}

声明我的长数组我一直在研究如何使用所有数组值创建.txt文件，然后使用arraylist。但每次我尝试失败。另外，一旦我弄清楚如何使用arraylist，我就需要使用： Toast.makeText(getBaseContext(), variable, Toast.LENGTH_SHORT).show呼唤我的arraylist的特定行。

任何帮助将不胜感激。谢谢！

Answer 1

我建议你创建一个JSON文件，如下所示

[
  "entryOne",
  "entryTwo",
  "...",
  "entryN"
]

现在将此文件存储在资源中，并按以下方式加载（感谢https://stackoverflow.com/a/13814551/7274758）

public String loadJSONFromAsset() {
    String json = null;
    try {
        InputStream is = getAssets().open("file_name.json");
        int size = is.available();
        byte[] buffer = new byte[size];
        is.read(buffer);
        is.close();
        json = new String(buffer, "UTF-8");
    }
    catch (IOException ex) {
        ex.printStackTrace();
        return null;
    }
    return json;
}

然后您可以尝试通过JSONArray

创建此JSON字符串的数组

JSONArray arr = new JSONArray(loadJSONFromAsset());

要从行中检索字符串，请致电getString - arr.getString (rowNo)

创建一个应用程序 - Java - 从.txt文件创建一个arraylist并烘烤特定的arraylist行

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