Question

如何使用不在JSON中但仍然是我在android中使用PHP接收的数组元素的列名称？这是我的PHP文件：

   {
        "items": [
        {
          "v_id": "1",
          "v_name": "Hotel Girija",
          "v_address": "Vijayanagar Colony, Municipal Colony, Pune,         Maharashtra 411030",
          "v_avg_rating": "3",
          "v_image": "http://i1.walesonline.co.uk/whats-on/food-drink-news/article7978981.ece/ALTERNATES/s615/MAin.jpg",
          "v_contact1": "8456217412"
        },
        {
          "v_id": "4",
          "v_name": "Pataleshwar hotel",
          "v_address": "Some addresss again",
          "v_avg_rating": "5",
          "v_image": "https://www.whatsuplife.in/gurgaon/blog/wp-content/uploads/2015/09/Chaat-Chowk.jpg",
          "v_contact1": "5452232554"
        }
      ],
      "sub_image": "http://www.asiansinamerica.org/wp- content/uploads/2016/08/Asian-and-Chinese-Food.jpg",
      "success": 1
    }

我必须使用以下内容获取关键项的所有值：

    JSONObject root = new JSONObject(items);
    JSONArray arr = root.getJSONArray("items");
    for (int i = 0; i < arr.length(); i++)
    {
        JSONObject obj = (JSONObject) arr.get(i);
        path = "" + obj.optString("v_image");
        // path = "http://" + path.replaceAll("\\s+", "%20");
        al_subcatdetl_id.add("" + obj.optString("v_id"));
        al_subcatdetl_name.add("" + obj.optString("v_name"));
        al_subcatdetl_addr.add("" + obj.optString("v_address"));
        al_subcatdetl_img.add("" + path);
        al_subcatdetl_rating.add("" + obj.optString("v_avg_rating"));

       ///al_subject_img.add(obj.getString("sub_image"));
    }

但我不知道如何获取 sub_image ，这是 item 之外的。如何实现这一目标？

Answer 1

在这种情况下，您可以直接从JSONObject

获取字符串

try {    
JSONObject root = new JSONObject(items);
String  subimage = root.getString("sub_image");
} catch(Exception ex){

}

如何获取不在JSON中的列名，但它仍然是我在android中使用PHP收到的数组元素

1 个答案: