我试图使用C#计算二度方程的结果,但我得到结果NaN
。有人可以检查我的代码以找到错误吗?
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace desafio2_2
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Please insert the values that multiply x², x and the independent term respectively: ");
float a = float.Parse(Console.ReadLine());
float b = float.Parse(Console.ReadLine());
float c = float.Parse(Console.ReadLine());
double bhaskarap1 = (Math.Pow(b, 2)) + (- 4 * a * c);
double raiz1 = (-b + Math.Sqrt(bhaskarap1)) / (2 * a);
double raiz2= (-b - Math.Sqrt(bhaskarap1)) / (2 * a);
Console.WriteLine(raiz1);
Console.WriteLine(raiz2);
}
}
}
答案 0 :(得分:3)
二次方程可能没有真正的根。在这种情况下,判别式将为负数。
当Math.Sqrt(x)
为负时, x
会返回NaN。在调用平方根函数之前,您应该测试负数的判别式。
static void Main(string[] args)
{
Console.WriteLine("Please insert the values that multiply x², x and the independent term respectively: ");
float a = float.Parse(Console.ReadLine());
float b = float.Parse(Console.ReadLine());
float c = float.Parse(Console.ReadLine());
double bhaskarap1 = (Math.Pow(b, 2)) + (- 4 * a * c);
if (bhaskarap1 < 0)
{
Console.WriteLine("There are no real solutions.");
return;
}
double raiz1 = (-b + Math.Sqrt(bhaskarap1)) / (2 * a);
double raiz2= (-b - Math.Sqrt(bhaskarap1)) / (2 * a);
Console.WriteLine(raiz1);
Console.WriteLine(raiz2);
}
答案 1 :(得分:1)
sqrt方法的参数必须是正的。
答案 2 :(得分:0)
一般情况下,二次方程的根是复数数,例如
x**2 + 1 = 0
这就是为什么我建议使用Complex
,而不是float
:
...
using System.Numerics;
...
// float.Parse - if you want to allow just real coefficients
Complex a = float.Parse(Console.ReadLine());
Complex b = float.Parse(Console.ReadLine());
Complex c = float.Parse(Console.ReadLine());
Complex bhaskarap1 = b * b - 4 * a * c;
Complex raiz1 = (-b + Complex.Sqrt(bhaskarap1)) / (2 * a);
Complex raiz2 = (-b - Complex.Sqrt(bhaskarap1)) / (2 * a);
Console.WriteLine(raiz1);
Console.WriteLine(raiz2);
答案 3 :(得分:0)
我会使用三元运算符检查NaN,如下所示,以处理sqrt的负值。
float a = 4.0f, b = 7.0f, c = -3.0f;
double my_var = ((Math.Pow(b, 2)) + (-4 * a * c));
Console.WriteLine(my_var);
Console.WriteLine(((-b + Math.Sqrt(-1 * my_var)) / (2 * a)));
double temp = (-b + Math.Sqrt(my_var)) / (2 * a);
double raiz1 = temp.CompareTo(Double.NaN) < 1 ? 0.00 : temp;
temp = (-b + Math.Sqrt(-1 * my_var)) / (2 * a);
double raiz2 = temp.CompareTo(Double.NaN) < 1 ? 0.00 : temp;
Console.WriteLine($"Raiz1: {raiz1}\tRaiz2: {raiz2}");
输出:
97
NaN
Raiz1: 0.356107225224513 Raiz2: 0