timestamp -mysql_fetch_assoc（）

Question

我希望我的程序遍历每一行并检查时间戳，如果时间戳超过两天，则在当前位置的列（街道）中插入5（数字），否则回显“天，小时，分钟”.. < / p>

更新：从OP PasteBin URL添加更新的代码：

<?php
//db conn............

 $lat= 7;
    $query='SELECT timestamp FROM users';
    $result = mysql_query($query);
    while ($row = mysql_fetch_assoc($result)) {

        $time = strtotime($row);
        $one_week_ago = strtotime('-1 day');
        $a=6;

        if( $time > $one_week_ago ) {    //not older than one day

           $p="UPDATE users SET  confirm ='$a'";
           if(mysql_query($p))
           {   
            echo "$a";
           }
           else{
               echo "wrong";
           }

         }
         else {  //older than one day
            $query="UPDATE users SET street= '$lat' WHERE confirm !=$a";

            if(mysql_query($query))
            {  
                echo "sucsessful <br>";
            }
            else {
                echo "unsuccessful <br>";
            }

         }

    }
?>

Answer 1

规范：我假设您的表格结构如下：

+---------+--------------+------+-----+--------------------+----------------+
| Field   | Type         | Null | Key | Default            | Extra          |
+---------+--------------+------+-----+--------------------+----------------+
| user_id | mediumint(9) | NO   | PRI | NULL               | auto_increment |
| timestamp |  timestamp | NO   |     | CURRENT_TIMESTAMP  |                |
| street  | int(10)      | NO   |     | 0                  |                |
| confirm | int(10)      | NO   |     | 0                  |                |
+---------+--------------+------+-----+--------------------+----------------+

解决方案：只需将代码替换为我的代码，如下所示：

<?php
//db conn............
 $lat= 7;
    $query='SELECT user_id, timestamp FROM users';
    $result = mysql_query($query);
    while ($row = mysql_fetch_assoc($result)) {
        $time = $row['timestamp'];
        $one_week_ago = date('Y-m-d H:i:s', strtotime('-1 day'));
        $a=6;
        if( $time > $one_week_ago ) {    //not older than one day
           $p="UPDATE users SET  confirm ='$a' where user_id = ".$row['user_id'];
           if(mysql_query($p))
           {   
            echo "$a";
           }
           else{
               echo "wrong";
           }
         }
         else {  //older than one day
            $query="UPDATE users SET street= '$lat' WHERE confirm !=$a and user_id = ".$row['user_id'];
            if(mysql_query($query))
            {  
                echo "sucsessful <br>";
            }
            else {
                echo "unsuccessful <br>";
            }
         }
    }
?>