如何从JS（ES6）中的forloop修复NaN？

Question

我正在使用JavaScript构建自己的数学课程。我将默认精度声明为8.当我将其传递给函数时，将for - 循环中的结果更改为NaN。

class Mathematics {
    constructor(angleType, accuracy) {
        this.PI = 3.1415926535897932384626433832795;
        this.at = angleType || "rad";
        this.acc = accuracy || 8;
    }

    Ang(angle, at) {
        let angdeg, angrad;
        switch (at) {
            case "deg" || "d" || "Deg":
                angdeg = angle;
                angrad = angdeg * this.PI / 180;
                break;
            case "rad" || "r" || "Rad":
                angrad = angle;
                break;
        }
        return angrad;
    }

    Sin(angle, at, acc) {
        let _at = at || this.at,
            angrad = this.Ang(angle, _at),
            ans = 1,
            _acc = acc || this.acc,
            temp = 1;
        for (let i = 2; i <= 2 * _acc; i += 2) {
            temp = temp * (-1) * angrad * angrad / (i * (i + 1));
            ans = ans + temp;
            console.log("sin " + i / 2 + ": " + ans);
        }
        return ans;
    }

    sin(angle, at, acc) { return this.Sin(angle, at, acc) }

    Cos(angle, at, acc) {
        let _at = at || this.at,
            angrad = this.Ang(angle, _at),
            ans = angrad,
            _acc = acc || this.acc,
            temp = 1;
        for (let i = 2; i <= 2 * _acc; i += 2) {
            temp = temp * (-1) * angrad * angrad / (i * (i - 1));
            ans = ans + temp;
            console.log("cos " + i / 2 + ": " + ans);
        }
        return ans;
    }

    cos(angle, at, acc) { return this.Cos(angle, at, acc) }

    Tan(angle, at, acc) { return this.Sin(angle, at, acc) / this.Cos(angle, at, acc) }

    tan(angle, at, acc) { return this.Tan(angle, at, acc) }
}
var MathClass = new Mathematics();

console.log("Class sin: " + MathClass.sin(1));
console.log("Math sin: " + Math.sin(1));
console.log("Class cos: " + MathClass.cos(1));
console.log("Math cos: " + Math.cos(1));
console.log("Class tan: " + MathClass.tan(1) + " an accuration of 8");
console.log("Class tan: " + MathClass.tan(1, "r", 9) + " an accuration of 9");
console.log("Math tan: " + Math.tan(1));

如果您运行代码段，您会看到for - 循环长度很好，但答案转为NaN。

您可以将构造函数中的精度编辑为9，并且在您更改最后一个参数之前它可以正常运行：MathClass.tan(1, "r", 5)

Answer 1

您的问题是，此语法不能用作在JavaScript中捕获多个案例的简写：

case "rad" || "r" || "Rad":

您需要使用多个case语句，如下所示：

case "rad":
case "r":
case "Rad":

修改或使用if / else和正则表达式：

Ang(angle, at) {
    at = at || this.at

    if (/^r(ad)?$/i.test(at)) {
        return angle
    } else if (/^d(eg)?$/i.test(at)) {
        return angle * this.PI / 180
    } else {
        throw new Error("Invalid angle type: " + at)
    }
}

演示片段：

＆＃13;

＆＃13;

class Mathematics {
    constructor(angleType, accuracy) {
        this.PI = 3.1415926535897932384626433832795;
        this.at = angleType || "rad";
        this.acc = accuracy || 8;
    }

    Ang(angle, at) {
        let angdeg, angrad;
        switch (at) {
            case "deg":
            case "d":
            case "Deg":
                angdeg = angle;
                angrad = angdeg * this.PI / 180;
                break;
            case "rad":
            case "r":
            case "Rad":
                angrad = angle;
                break;
        }
        return angrad;
    }

    Sin(angle, at, acc) {
        let _at = at || this.at,
            angrad = this.Ang(angle, _at),
            ans = 1,
            _acc = acc || this.acc,
            temp = 1;
        for (let i = 2; i <= 2 * _acc; i += 2) {
            temp = temp * (-1) * angrad * angrad / (i * (i + 1));
            ans = ans + temp;
            console.log("sin " + i / 2 + ": " + ans);
        }
        return ans;
    }

    sin(angle, at, acc) { return this.Sin(angle, at, acc) }

    Cos(angle, at, acc) {
        let _at = at || this.at,
            angrad = this.Ang(angle, _at),
            ans = angrad,
            _acc = acc || this.acc,
            temp = 1;
        for (let i = 2; i <= 2 * _acc; i += 2) {
            temp = temp * (-1) * angrad * angrad / (i * (i - 1));
            ans = ans + temp;
            console.log("cos " + i / 2 + ": " + ans);
        }
        return ans;
    }

    cos(angle, at, acc) { return this.Cos(angle, at, acc) }

    Tan(angle, at, acc) { return this.Sin(angle, at, acc) / this.Cos(angle, at, acc) }

    tan(angle, at, acc) { return this.Tan(angle, at, acc) }
}
var MathClass = new Mathematics();

console.log("Class sin: " + MathClass.sin(1));
console.log("Math sin: " + Math.sin(1));
console.log("Class cos: " + MathClass.cos(1));
console.log("Math cos: " + Math.cos(1));
console.log("Class tan: " + MathClass.tan(1) + " an accuration of 8");
console.log("Class tan: " + MathClass.tan(1, "r", 9) + " an accuration of 9");
console.log("Math tan: " + Math.tan(1));

＆＃13;

＆＃13;

＆＃13;