由于某种原因,OkHttp response.cacheResponse()
总是返回null,即使请求应该被缓存。在下面的代码中我向http://httpbin.org/cache/60
提出两个请求,我希望,第二个请求将从缓存中获取。但从输出中可以看出它不是。
我错过了什么?
代码:
@Test
public void test2_okhttp() throws IOException {
int cacheSize = 100 * 1024 * 1024; // 100 MiB
File cacheDir = new File("/tmp/ok_cache");
cacheDir.mkdirs();
Cache cache = new Cache(cacheDir, cacheSize);
OkHttpClient client = new OkHttpClient.Builder()
.cache(cache)
.build();
String url = "http://httpbin.org/cache/60";
for(int i = 0; i < 2; i++) {
Request request = new Request.Builder()
.url(url)
.build();
Response response = client.newCall(request).execute();
System.out.println("response1.cacheResponse() = " + response.cacheResponse());
System.out.println("response1.networkResponse() = " + response.networkResponse());
}
}
输出:
response1.cacheResponse() = null
response1.networkResponse() = Response{protocol=http/1.1, code=200, message=OK, url=http://httpbin.org/cache/60}
response1.cacheResponse() = null
response1.networkResponse() = Response{protocol=http/1.1, code=200, message=OK, url=http://httpbin.org/cache/60}
答案 0 :(得分:2)
OkHttp将响应主体写入缓存,作为您阅读正文的副作用。拨打response.body().string()
即可,或者您可以通过其他方式阅读正文。