Question

我可以运行：

awk -v DATE="$(date +"%d%m%Y")" 'BEGIN{print DATE }1''1; END{print "EOF"NR-1}' Assgmt_B1_v1_16032017.CSV  > NoticesPrinting_v1_farah.csv

但参数化后，我再也无法跑了......请帮助我。

 Today_Date=`date +"%d%m%Y"`
 Current_Date=`date +"%d%m%Y"`


awk -v DATE="${Today_Date}" path="${Target_Dir}"'BEGIN{print DATE};END{print "EOF"NR-1}' "${Source_Dir}/${log}" > file= path ""NoticesPrinting_v1".csv"

输入：

Header 1|Header 2|Header 3
10000001|10000002|10000003

输出：

17032017
Header 1|Header 2|Header 3
10000001|10000002|10000003
EOF1

Answer 1

您的情况下语法错误

awk -v DATE="$(date +"%d%m%Y")" 'BEGIN{print DATE }1''1; END{print "EOF"NR-1}' Assgmt_B1_v1_16032017.CSV  > NoticesPrinting_v1_farah.csv
                                                     ^
                                                    Here unnecessary quote

像这样纠正

awk -v DATE="$(date +"%d%m%Y")" 'BEGIN{print DATE }1; END{print "EOF"NR-1}' Assgmt_B1_v1_16032017.CSV  > NoticesPrinting_v1_farah.csv

和

awk -v DATE="${Today_Date}" path="${Target_Dir}"'BEGIN{print DATE};END{print "EOF"NR-1}' "${Source_Dir}/${log}" > file= path ""NoticesPrinting_v1".csv" ^ ^ Missing -v Missing space ^ O/p redirection

如下所示纠正

awk -v DATE="${Today_Date}" -v path="${Target_Dir}" ' BEGIN{print DATE}; END{print "EOF"NR-1} ' "${Source_Dir}/${log}" > "NoticesPrinting_v1.csv"

和反引号（`...`）是最老的非POSIX兼容的bourne-shell所需的遗留语法，$(...)是POSIX，更优选，至少{{1}在视觉上更突出。

$(...)

要

Today_Date=`date +"%d%m%Y"`

请参阅：Why is $(...) preferred over (`...`) (backticks)?

回答评论

输出结果但只有标题和预告片...输出不会出现

Today_Date=$(date +"%d%m%Y")

用于参数化的AWK命令

1 个答案: