INSERT INTO counters (REQUEST_ID, MODIFIED_DATE_WFM)
SELECT
si_id, MAX(modified_date) AS field
FROM tt
group by si_id
ON DUPLICATE KEY UPDATE
MODIFIED_DATE_WFM = VALUES(modified_date)
错误SQL(1054):“字段列表”中的未知列'modified_date'
我试过使用子查询:
select * from (SELECT
si_id, MAX(modified_date) AS field
FROM tt
group by si_id) sub1
和别名:
ON DUPLICATE KEY UPDATE
MODIFIED_DATE_WFM = VALUES(field)
但请选择:
SELECT
si_id, MAX(modified_date) AS field
FROM tt
group by si_id
是工作
FOR TEST: FITS TABLE:
CREATE TABLE `counters` (
`REQUEST_ID` BIGINT(20) NULL DEFAULT NULL,
`MODIFIED_DATE_WFM` INT(11) NULL DEFAULT NULL,
UNIQUE INDEX `REQUEST_ID` (`REQUEST_ID`)
)
COLLATE='utf8_general_ci'
ENGINE=InnoDB
;
第二表:
CREATE TABLE `tt` (
`si_id` BIGINT(20) NOT NULL,
`modified_date` INT(11) NOT NULL,
INDEX `si_id` (`si_id`)
)
COLLATE='utf8_general_ci'
ENGINE=InnoDB
;
DATA:
INSERT INTO `tt` VALUES (2574604, 1486086672);
INSERT INTO `tt` VALUES (2574604, 1487116221);
INSERT INTO `tt` VALUES (2574604, 1487971423);
INSERT INTO `tt` VALUES (2574604, 1488136028);
INSERT INTO `tt` VALUES (2574604, 1488136324);
INSERT INTO `tt` VALUES (2574604, 1488524248);
INSERT INTO `tt` VALUES (2574604, 1488728989);
INSERT INTO `tt` VALUES (2834403, 1488782168);
服务器版本:5.7.16 MySQL社区服务器(GPL)
答案 0 :(得分:1)
您在更新时的更新错误。试试吧:
INSERT INTO counters (REQUEST_ID, MODIFIED_DATE_WFM)
SELECT
si_id, MAX(modified_date) AS `field`
FROM tt
group by si_id
ON DUPLICATE KEY UPDATE
MODIFIED_DATE_WFM = VALUES(MODIFIED_DATE_WFM);