Question

我正在开发一个脚本，我有一个十六进制字符串31323334353637383930313233，我想将其转换为ASCII。期望的输出为1234567890123。

我已经使用它了：

echo "31323334353637383930313233" | xxd -r -p

或

echo "31323334353637383930313233" | perl -pe 's/(..)/chr(hex($1))/ge'

但重点是尝试使用脚本的最低可能要求。我希望它在suse，fedora，debian，ubuntu，arch等工作......似乎xxd命令包含在vim包中。我想知道是否有办法使用awk或任何内部Linux工具来实现这一点，默认情况下将在所有Linux系统中使用。

谢谢。

Answer 1

找到此脚本.filter：

hex2string "31323334353637383930313233"

您可以更改行#!/bin/bash function hex2string () { I=0 while [ $I -lt ${#1} ]; do echo -en "\x"${1:$I:2} let "I += 2" done } hex2string "$1" echo，使其从参数中获取十六进制值，即：

./hexstring.sh 31323334353637383930313233

所以当执行时：

from Tkinter import *

def printSomething():
    # if you want the button to disappear:
    # button.destroy() or button.pack_forget()
    label = Label(root, text= "Hey whatsup bro, i am doing something very interresting.")
    #this creates a new label to the GUI
    label.pack() 

root = Tk()

button = Button(root, text="Print Me", command=printSomething) 
button.pack()

root.mainloop()

它将提供所需的ascii输出。

注意：无法测试它是否适用于所有Linux系统。

Answer 2

使用gawk，从HEX到ASCII

$ gawk  '{ 
           gsub(/../,"0x& "); 
           for(i=1;i<=NF;i++)
              printf("%c", strtonum($i)); 
           print "" 
}' <<<"31323334353637383930313233"
1234567890123

使用任何awk

$ cat hex2asc_anyawk.awk 
BEGIN{
    split("0 1 2 3 4 5 6 7 8 9 A B C D E F", d, / /)
    for(i in d)Decimal[d[i]]=i-1
}

function hex2dec(hex,  h,i,j,dec)
{ 
    hex = toupper(hex);                
    i   = length(hex);                 
    while(i)
    {  
          dec += Decimal[substr(hex,i,1)] * 16 ^ j++
          i--                          
    }
    return dec;
}
{

    gsub(/../,"& "); 
    for(i=1;i<=NF;i++)
        printf("%d",hex2dec($i));
    print ""
}

<强>执行

$ awk -f hex2asc_anyawk.awk <<<"31323334353637383930313233"
1234567890123

<强>解释

步骤：

从表中获取十六进制等效值。
将每位数字乘以16位数字位置。
求和所有乘数。

示例：

BEGIN{
    # Here we created decimal conversion array, like above table
    split("0 1 2 3 4 5 6 7 8 9 A B C D E F", d, / /)
    for(i in d)Decimal[d[i]]=i-1
}

function hex2dec(hex,  h,i,j,dec)
{ 
    hex = toupper(hex);                 # uppercase conversion if any A,B,C,D,E,F
    i   = length(hex);                  # length of hex string
    while(i)
    {  
          # dec var where sum is stored
          # substr(hex,i,1) gives 1 char from RHS
          # multiply by 16 power of digit location 
          dec += Decimal[substr(hex,i,1)] * 16 ^ j++
          i--                           # decrement by 1
    }
    return dec;
}
{
    # it modifies record
    # suppose if given string is 31323334353637383930313233
    # after gsub it becomes 31 32 33 34 35 36 37 38 39 30 31 32 33
    # thus re-evaluate the fields

    gsub(/../,"& "); 

    # loop through fields , NF gives no of fields
    for(i=1;i<=NF;i++)

        # convert from hex to decimal
        # and print equivalent ASCII value 
        printf("%c",hex2dec($i));

    # print newline char
    print ""
}

dec += Decimal[substr(hex,i,1)] * 16 ^ j++
的含义

dec += Decimal[substr(hex,i,1)] * 16 ^ j++
 ^           ^                    ^
 |           |                    | 
 |           |                    2.Multiply every digit with 16 power of digit location.
 |           |    
 |           1.Gives decimal equivalent of hex
 | 
 | 
 3. Sum all the multipliers

Answer 3

替代（g）awk解决方案：

echo "31323334353637383930313233" | awk 'RT{printf "%c", strtonum("0x"RT)}' RS='[0-9]{2}'

击。十六进制到ascii。没有xxd或perl可能吗？

3 个答案: