我正在尝试将表单从jquery-mobile页面提交到php文件进行处理,但每当我按下提交按钮时,它都会显示“错误加载页面”对话框。
我已尝试查看w3schools website表单提交示例,并且我非常确定我的代码是相同的。这是我的代码。
的index.html
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Jquery Mobile</title>
<!-- Include meta tag to ensure proper rendering and touch zooming -->
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- Include jQuery Mobile stylesheets -->
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css">
<!-- Include the jQuery library -->
<script src="https://code.jquery.com/jquery-1.11.3.min.js"></script>
<!-- Include the jQuery Mobile library -->
<script src="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
<style>
.ui-content {
margin-top:150px;
margin-left:500px;
margin-right:500px;
}
/* For mobile screens */
@media screen and (max-width: 480px) {
.ui-content{
margin:0px;
}
</style>
</head>
<body>
<div data-role="page" id="chat">
<div data-role="header"><h1>Welcome to the Streamline Chat App</h1></div>
<div data-role="main" class="ui-content">
<h3>Select a username to continue</h3>
<form method="post" action="login.php">
<label for="username" >Username:</label>
<input type="text" id="username" name="username">
<input type="submit" data-inline="true" value="Submit">
</form>
</div>
</div>
</body>
</html>
的login.php
<?php
$username = $_POST['username'];
echo $username;
?>
我想知道我做错了什么。请帮帮我。两个文件都在同一目录中
答案 0 :(得分:0)
我从另一篇帖子here
得到了答案只需将data-ajax="false"
添加到表单标记
<form method="post" action="login.php" data-ajax="false">
<label for="username" >Username:</label>
<input type="text" id="username" name="username">
<input type="submit" data-inline="true" value="Submit">
</form>