将XML内容插入到mysql DB

时间:2017-03-14 12:18:49

标签: php mysql xml insert

基本上我有一个调用外部XML文件的php脚本

然后,它将xml文件中的某些数据插入到foreach循环中的mysql数据库中

但是当我检查数据库时它是空的

我做错了什么

xml包含以下结构

<jobs>
    <job>
        <jobref>987654321</jobref>
        <title>TITLE HERE</title>
        <url>
        URL HERE
        </url>
        <salary>&pound;85 - &pound;105/day benifits</salary>
        <location>LOCATION</location>
        <description>desc</description>
        <category>CAT HERE</category>
    </job>
    <job>
        <jobref>123456789</jobref>
        <titleTITLE HERE</title>
        <url>
        URL HERE
        </url>
        <salary>&pound;85 - &pound;105/day benifits</salary>
        <location>LOCATION</location>
        <description>desc</description>
        <category>CAT</category>
    </job>
</jobs>

以下是PHP代码

<?php
    $dbu = 'user';
    $dbp = 'pass';
    $dbh = 'localhost';
    $dbn = 'dbname';

    $dbc = mysql_pconnect($dbh,$dbu,$dbp);

    // Get XML Feed
    $startPage = $_GET['page'];
    $perPage = 3000;
    $currentRecord = 0;
    $xml = simplexml_load_file("urlhere");
    $jobs = $xml->xpath("/jobs/job");

    foreach ($jobs as $job)
    {
        mysql_select_db($dbn,$dbc);
        $query = mysql_query("INSERT INTO `listings` (`jobref`,`title`,`url`,`salary`,`location`,`description`,`category`) VALUES ('$job->jobref','$job->title','$job->salary','$job->location','$job->description','$job->category')",$dbc);

        echo "$job->jobref Added <br>";
    }
?>

显示:

120239811 Added 
201909016 Added 
202482907 Added 

当我运行脚本以便解析xml文件但实际上并没有插入数据时

任何帮助都会很棒,因为我在非常紧迫的时间内完成了这项工作 提前致谢

**以下编辑** 下面的新代码

<?php
        $startPage = 1;
        $perPage = 3000;
        $currentRecord = 0;
        $xml = simplexml_load_file("urlhere");
        $jobs = $xml->xpath("/jobs/job");
        mysql_select_db($dbn,$dbc);
        foreach ($jobs as $job)
        {
        $currentRecord += 1;
         if($currentRecord > ($startPage * $perPage) && $currentRecord < ($startPage * $perPage + $perPage)){ 
        $query = mysql_query("INSERT IGNORE INTO `listings` (jobref,title,url,salary,location,description,category) VALUES ('$job->jobref','$job->title','$job->url','$job->salary','$job->location','$job->description','$job->category')",$dbc);
        if($query){
        echo "$job->jobref Added <br>";
        } else {
        echo mysql_error();
        }
        }
        }
        ?>

现在只需添加XML文件中的第一个条目

从查询中删除了IGNORE并添加了      ON DUPLICATE KEY UPDATE jobref = $ job-&gt; jobref + 1 还是同样的问题

1 个答案:

答案 0 :(得分:0)

你确定xml成功加载了吗? :)但我猜你的样本中xml节点<salary>有非法的&符号"&" here the link about it

但你可以通过一点点破解like this处理它。

我建议您使用mysqli,因此根据您的xml示例

...

$conn = mysqli_connect($dbh, $dbu, $dbp);
if(!$conn) die('connect fail: '. mysqli_error($conn));

$db = mysqli_select_db($conn, $dbn);
if(!$db) die('db fail: '. mysqli_error($conn));

... 

$file = file_get_contents(url_here);

// replace '&' to '&amp;'
$file = str_replace('&', '&amp;', $file);
$xml = simplexml_load_string($file);

$jobs = $xml->xpath("/jobs/job");

foreach ($jobs as $job)
{
    ...

    // just get back those ampersand
    $job->salary = str_replace('&amp;', '&', $job->salary);

    $s = "INSERT IGNORE INTO `listings` (`jobref`,`title`,`url`,`salary`,`location`,`description`,`category`) VALUES('$job->jobref','$job->title','$job->url','$job->salary','$job->location','$job->description','$job->category')";

    $q = mysqli_query($conn, $s);

    if(!$q) {
        die(mysqli_error($conn));
    }else {
        echo "$job->jobref Added <br>";
    }
}