这是我在下面的php代码
$token = md5(uniqid(rand(), true));
$complete = 'No';
$update_sql = "CALL updatetoken ('$db_email','$token','$complete')";
echo $update_sql;
// $update_sql = "UPDATE user SET resetToken = {$token}, resetCompleted='No' WHERE email = {$_POST['email']}";
$sqlfile = mysqli_query($connection, $update_sql);
if ($sqlfile) {
echo "Update successful";
} else {
echo "Error updating the database";
}
然后是存储过程
CREATE DEFINER=`root`@`localhost` PROCEDURE `updatetoken` (IN `usermail` VARCHAR(100), IN `token` VARCHAR(100), IN `completetask` VARCHAR(100)) UPDATE user SET resetToken = token, resetCompleted = completetask WHERE email = usermail$$
而不是更新数据库,我不断收到错误消息“更新数据库时出错”,我尝试使用普通的“INSERT”mysql方法从我的PHP代码而不是CALL,但仍然是相同的错误消息
答案 0 :(得分:0)
答案 1 :(得分:0)
token = md5(uniqid(rand(), true));
$complete = 'No';
$update_sql = "CALL updatetoken ('$db_email','$token','$complete')";
echo $update_sql;
// $update_sql = "UPDATE user SET resetToken = {$token}, resetCompleted='No' WHERE email = {$_POST['email']}";
$sqlfile = mysqli_query($connection, $update_sql);
if ($sqlfile) { echo "Update successful"; }
else { echo "Error updating the database";`